There are 0.566 moles of carbonate in sodium carbonate.
<h3>CALCULATE MOLES:</h3>
- The number of moles of carbonate (CO3) in sodium carbonate (Na2CO3) can be calculated by dividing the mass of carbonate in the compound by the molar mass of the compound.
- no. of moles of CO3 = mass of CO3 ÷ molar mass of Na2CO3
- Molar mass of Na2CO3 = 23(2) + 12 + 16(3)
- = 46 + 12 + 48 = 106g/mol
- mass of CO3 = 12 + 48 = 60g
- no. of moles of CO3 = 60/106
- no. of moles of CO3 = 0.566mol
- Therefore, there are 0.566 moles of carbonate in sodium carbonate.
Learn more about number of moles at: brainly.com/question/1542846
<em><u>look at the clues by it and try not to trust the links they trying to give u...</u></em>
<em><u>but i kinda dont know myself any periodic table i can look at?</u></em>
<u>Answer:</u> The given amount of iron reacts with 9.0 moles of
and produce 6.0 moles of 
<u>Explanation:</u>
We are given:
Moles of iron = 12.0 moles
The chemical equation for the rusting of iron follows:

By Stoichiometry of the reaction:
4 moles of iron reacts with 3 moles of oxygen gas
So, 12.0 moles of iron will react with =
of oxygen gas
- <u>For iron (III) oxide:</u>
By Stoichiometry of the reaction:
4 moles of iron produces 2 moles of iron (III) oxide
So, 12.0 moles of iron will produce =
of iron (III) oxide
Hence, the given amount of iron reacts with 9.0 moles of
and produce 6.0 moles of 
Answer:
Ag⁺(aq) + Cl⁻(aq) ==> AgCl(s)
Explanation:
The net ionic equation can be described as the equation that contains only those species which would be participated in the chemical reaction. The spectator ions are the type of the ions that are present in both sides of the chemical equation these ions could not be present in the net ionic equation
First, it is easiest if you write the compete molecular equation:
AgNO₃(aq) + KCl(aq) ⇔ AgCl(s) + KNO₃(aq)
we look up which compounds are soluble (aq) and which are not (s). In this case, silver chloride (AgCl) is not soluble. Thus, the net ionic equation is...
Ag⁺(aq) + Cl⁻(aq) ==> AgCl(s)