Answer:
2x + 3y = 18 sum of charges of the iron ions must be +18 to balance 18 CN- ... y = 4 so there are 4 Fe3+ ions and (7–4) = 3
<h3><u>Answer</u>;</h3>
19 mg
<h3><u>Explanation</u>;</h3>
dose = 5.0 mg/kg
weight of infant = 8.5 pounds
Convert 8.5 pounds to kg: 8.5 pounds = 3.86 kg
Therefore;
The dose to give the infant is:
= (5.0 mg/kg) x (3.86 kg)
= 19.3 mg
<u>≈ 19 mg</u>
Answer:?Any one have the answers?
Explanation:d
<u>We are given:</u>
Mass of NaCl in the given solution = 22.3 grams
Volume of the given solution = 2 L
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<u>Number of Moles of NaCl:</u>
We know that the number of moles = Given mass / Molar mass
Number of moles = 22.3 / 58.44 = 0.382 moles
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<u>Molarity of NaCl in the Given solution:</u>
We know that Molarity of a solution = Moles of Solute / Volume of Solution(in L)
Molarity = 0.382 / 2
Molarity = 0.191 M
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Answer:
Mass = 10.1 g
Explanation:
Given data:
Mass of Fe₂O₃ produced = ?
Mass of iron rust = 12.0 g
Solution:
Chemical equation:
4Fe + 3O₂ → 2Fe₂O₃
Number of moles of iron:
Number of moles = mass/ molar mass
Number of moles = 12.0 g/ 55.85 g/mol
Number of moles = 0.215 mol
Now we will compare the moles of iron and Fe₂O₃ .
Fe : Fe₂O₃
4 : 2
0.215 : 2/4×0.125 = 0.063 mol
Mass of Fe₂O₃ :
Mass = number of moles × molar mass
Mass = 0.063 mol × 159.7 g/mol
Mass = 10.1 g
