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alex41 [277]
3 years ago
14

When limestone (which is principally CaCO3) is heated, carbon dioxide and quick- lime (Cao) are produced by the reaction CaCO3(s

) Cao(s) + CO2(g). If 17.6 g of CO2 was produced from the ther- mal decomposition of 40.92 g of CaCO3, what is the percentage yield of the reaction? Answer in units of %.​
Chemistry
1 answer:
anyanavicka [17]3 years ago
7 0

Answer:

B.They show that the speaker’s memories come from various senses and seasons.

B.They show that the speaker’s memories come from various senses and seasons.

Explanation:

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Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:
Temka [501]

The question is incomplete , complete question is:

Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:

(a) n = 2 to n = 4

(b) n = 2 to n = 1

(c) n = 2 to n = 5

(d) n = 4 to n = 3

Answer:

Hence the order of the transition will be : d < a < c < b

Explanation:

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6 eV

Energy of n = 2 in an hydrogen atom:

E_2=-13.6\times \frac{1^2}{2^2}eV=-3.40eV

Energy of n = 3 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy of n = 4 in an hydrogen atom:

E_4=-13.6\times \frac{1^2}{4^2}eV=-0.85 eV

Energy of n = 5 in an hydrogen atom:

E_5=-13.6\times \frac{1^2}{5^2}eV=-0.544 eV

a) n = 2 to n = 4 (absorption)

\Delta E_1= E_4-E_2=-0.85eV-(-3.40eV)=2.55 eV

b) n = 2 to n = 1 (emission)

\Delta E_2= E_1-E_2=-13.6 eV-(-3.40eV)=-10.2 eV

Negative sign indicates that emission will take place.

c) n = 2 to n = 5 (absorption)

\Delta E_3= E_5-E_2=-0.544 eV-(-3.40eV)=2.856 eV

d) n = 4 to n = 3 (emission)

\Delta E_4= E_3-E_4=-1.51 eV-(-0.85 eV)=-0.66 eV

Negative sign indicates that emission will take place.

According to Planck's equation, higher the frequency of the wave higher will be the energy:

E=h\nu

h = Planck's constant

\nu frequency of the wave

So, the increasing order of magnitude of the energy difference :

E_4

And so will be the increasing order of the frequency of the of the photon absorbed or emitted. Hence the order of the transition will be :

: d < a < c < b

7 0
4 years ago
Make sure to explain your answer to each question part.
Vladimir [108]
I have the same question why can’t I accept this comment HELPPP 3737
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