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Anarel [89]
2 years ago
9

H2CO: → H2O + CO2

Chemistry
1 answer:
GaryK [48]2 years ago
4 0

Answer:

1) 2

2) 1

3)1

4) 2

5)3

6)1

7)yes except Oxygen

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Two airplanes are flying in the sky in such a way that the gravitational attractions between them decreases. The planes must be
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A. away from each other
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At a certain temperature the rate of this reaction is first order in SO₃ with a rate constant of 0.208 s⁻¹:
NNADVOKAT [17]

Answer:

0.30 M

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t  = ?

[A_0] is the initial concentration  = 1.36 M

k is the rate constant = 0.208 s⁻¹

t = 7.30 seconds

So,  

[A_t]=1.36\times e^{-0.208\times 7.30}\ M=0.30\ M

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3 years ago
Why do we sometimes use roman numerals in naming ionic compounds?
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Roman numerals are used in naming ionic compounds when the metal cation forms more than one ion. The metals that form more than one ion are the transition metals, although not all of them do this.
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Each square of the periodic table shows information about one element. The square usually shows the element's
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3 years ago
1.
german

Order of metals from least reactive to most reactive: B <C <A <D

<h3>Further explanation</h3>

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series  

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction  

Let's analyze the statement in the problem

I. Only A, C and D react with 1 mol/L HCl to give H₂(e)

M + HCl ⇒ MCl + H₂(MCl : alkali, MCl₂ : alkaline earth)

A, C and D can react with 1 mol / L HCl, meaning metals A, C and D are located to the left of element H (more reactive), and B in the right of element H

II. When A is added to solutions of the other metal ions, metallic B and C are  formed but not D.

This means that metal A is more reactive than metals B and C, while D is more reactive than A, so metal D is the most reactive

3 0
2 years ago
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