HNO3 + HI = NO + I2 + H2O

1 answer:

5 0

N goes from +5 to +2, a gain of 3 electrons
Each I goes from -1 to 0, a loss of 1 electron
Need a 3:1 ratio of HI to HNO3
Since I is I2 on the product side, use a 6:2 ratio
2HNO3 + 3HI= 2NO + 3I2 + 4H2O

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