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pickupchik [31]
2 years ago
7

I need you show me your answer for number 51

Mathematics
2 answers:
VladimirAG [237]2 years ago
6 0
Graph A is the answer
Just loon at the x and y
iragen [17]2 years ago
5 0
It's graph C. because on the first pair of numbers you can see that they both line up with the graph. Also, if you find the pattern between the numbers (x-3 and y-1) the graph C. lines up.

Hoped I helped! :)
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What is the GCF of, 33,22? I need this now.
Solnce55 [7]

Answer:

11

Step-by-step explanation:

33÷11=3

22÷11=2

3 and 2 habe no common factors

3 0
3 years ago
you can use a calculator if you want. No links please help this is very important i will give you brain thing if its correct
erica [24]

Answer:

Step-by-step explanation:

0.25 x 0.044 = 0.011

a. Changing 0.25 to 25 moves the decimal 2 places to the right, and changing 0.044 to 44 moves the decimal 3 places to the right, so once we solve 25 x 44, we have to move the decimal a total of 5 places to the left.

25 x 44 = 1100, then move the decimal 5 places to the left to get 0.01100...but we don't add the zeros at the end.

b. multiplying 1/4 times 0.044 = 0.044/4 = 0.011

Hope this helps.

8 0
2 years ago
What is a perfect squares​
erica [24]

Answer:

What is a Perfect Square? A perfect square is a number which is generated by multiplying two equal integers by each other. For example, number 9 is a perfect square because it can be expressed as a product two equal integers being: 9 = 3 x 3.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Anyone in connections academy algebra 2 or someone else that can help me with some problems? Here is the first: Let f(x)=2x^2+x-
sergiy2304 [10]
F(x)/g(x) = (2x +3)(x -1)/(x -1) = 2x +3 . . . . . x ≠ 1

The domain of (f/g)(x) is all real numbers except 1.

_____
The domain of any rational function necessarilly excludes any values that make the function undefined, that is, that make the denominator zero.
3 0
3 years ago
Answer please VVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVV
mezya [45]

\left[\begin{array}{ccc}3 & 9 \\\\ 5& -2\end{array}\right]+\left[\begin{array}{ccc}6 & 0\\\\ \!\!-8 & 4\end{array}\right]=\left[\begin{array}{ccc} 3+6 & 9+0 \\\\5-8 &-2+4 \end{array}\right] =\left[\begin{array}{ccc} 9& 9 \\\\ -3 & 2\end{array}\right]

6 0
2 years ago
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