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choli [55]
2 years ago
13

SCALCET8 3.8.001.MI. A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day

zero the population consists of two members. Find the population size after seven days. (Round your answer to the nearest whole number.) P(7)
Mathematics
1 answer:
Orlov [11]2 years ago
3 0

Answer:

A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day zero the population · Q: For this discussion, you will work in groups to find the area and answer questions.

Step-by-step explanation:

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Find the greatest common factor of x^2y and xy^2
Dimas [21]
1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
6 0
3 years ago
Chaney deposits $1435.73 into a savings account that pays a simple annual interest rate of 1.32%. How much interest will she ear
Aneli [31]

Answer:

Interest Chaney earns after 3 years is  $56.85

Step-by-step explanation:

Given:

Amount deposited = $1435.73

Simple annual interest rate = 1.32% = 1.32/ 100 = 0.0132

To find: Interest after 3 years

We know that the formula to calculate the interest amount is

Simple interest (S.I.) = \frac{Prt}{100}

where,

P is the initial amount deposited

r is the rate of simple interest in percentage

t is the time in years for which interest is to be calculated

Substituting the known values in the formula, we get

S.I = \frac{1435.73 x 1.32 x 3}{100}

    = 56.85

Hence the interest Chaney earns after 3 years is  $56.85

8 0
3 years ago
at a track meet,Jacob and daniel compete in 220 m hurdles. Daniels finishes in 3/4 of the a min.Jacob finishes with 5/12 of a mi
Savatey [412]
Jacob has the faster time because if you make the fractions equal you would make the denominators equal by rounding 3/4 to have a denominator of 12 making it 9/12 which is larger then 5/12 making Daniel's time slower then Jacob's.

3 0
3 years ago
Scarlett is trying to find the height of a dam. She stands 90 meters away from the dam and records the angle of elevation to the
andrew-mc [135]
90(tan26) + 1.65 = about 107.7378 meters
3 0
3 years ago
The number of bacteria in a refrigerated food product is given by N ( T ) = 22 T 2 − 123 T + 40 , 6 < T < 36 , where T is
antoniya [11.8K]

Answer:

N(T(t)) = 1408t^2 - 385.6t - 105.52

Time for bacteria count reaching 8019: t = 2.543 hours

Step-by-step explanation:

To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:

N(T(t)) = 22 * (8t + 1.7)^2  - 123 * (8t + 1.7) + 40

N(T(t)) = 22 * (64t^2 + 27.2t + 2.89) - 984t - 209.1 + 40

N(T(t)) = 1408t^2 + 598.4t + 63.58 -  984t - 169.1

N(T(t)) = 1408t^2 - 385.6t - 105.52

Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:

8019 = 1408t^2 - 385.6t - 105.52

1408t^2 - 385.6t - 8124.52 = 0

Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.

4 0
3 years ago
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