Ask question

Ask question

All categories

4 years ago

13

How much time passes when an object travels at a constant speed of 17 m/s over a distance of 323 m? Identify Variables, write fo

rmula, show work, label your answer.

1 answer:

k0ka [10]4 years ago

8 0

Answer: 19 s

Explanation:

The relationship between speed, distance and time is given by:

velocity= distance/time

time= distance/velocity= 323 m/17 m/s= 19 s

You might be interested in

Can someone please help me

Y_Kistochka [10]

#3). The wavelengths of the four types of electromagnetic
radiation on that list line up like this:

Longest ... microwaves
next . . . . . infrared waves
next . . . . . visible light waves
shortest ... ultraviolet waves

#4). The word "visible" means "able to be seen". Infrared
light and ultraviolet light are not visible to human eyes.

4 0

3 years ago

A 90.0-kg man runs at a constant speed of 11.5 m/s. what is his kinetic energy?

harina [27]

The kinetic energy possessed by the man is 517.5 Joules.

<u>Given the following data:</u>

Mass = 90.0 kg

Velocity = 11.5 m/s.

To find the kinetic energy of the man:

Kinetic energy is an energy that is possessed by a physical object or body due to its motion.

Mathematically, kinetic energy is calculated by using the formula;

$K.E = \frac{1}{2} MV^2$

<u>Where:</u>

K.E is the kinetic energy.

M is the mass of an object.

V is the velocity of an object.

Substituting the given values, we have;

$K.E = \frac{1}{2}$ × $90$ × $11.5$

$K.E = 45$ × $11.5$

<em>Kinetic energy = 517.5 Joules.</em>

Therefore, the kinetic energy possessed by the man is 517.5 Joules.

Read more: brainly.com/question/23153766

8 0

3 years ago

Many kinds of analysis in the physical sciences are helped by identifying quantities that are constant. It is usual to begin by

AysviL [449]

Answer:

As, there are different physical quantities which are required to be measured in a more proper way to define the circuits properties.

As, there is current,I which is the more directed flow of electrons inside the circuit.
Along, with which the voltage,V or in other words the potential difference inside the circuit is also taken under consideration.
And most importantly the resistance's,R value inside the circuit defines the parameters inside the circuit.
All of these values are then determined or analyzed with the help of the digital multi-meter or simply the DMM.

8 0

3 years ago

A cylindrically shaped piece of collagen (a substance found in the body in connective tissue) is being stretched by a force that

Marat540 [252]

Answer:

Part(a): The value of the spring constant is $3.11 \times 10^{2}~Kg~s^{-2}$ .

Part(b): The work done by the variable force that stretches the collagen is $1.5 \times 10^{-6}~J$ .

Explanation:

Part(a):

If ' $k$ ' be the force constant and if due the application of a force ' $F$ ' on the collagen ' $\Delta l$ ' be it's increase in length, then from Hook's law

$F = k~\Delta l....................................................................(I)$

Also, Young's modulus of a material is given by

$Y = \dfrac{F/A}{\Delta l/l}...............................................................(II)$

where ' $A$ ' is the area of the material and ' $l$ ' is the length.

Comparing equation ( $I$ ) and ( $II$ ) we can write

$&& Y = \dfrac{l~k}{A}\\&or,& k = \dfrac{Y~A}{l}\\&or,& k = \dfrac{Y~(\pi~r^{2})}{l}$

Here, we have to consider only the circular surface of the collagen as force is applied only perpendicular to this surface.

Substituting the given values in equation ( $III$ ), we have

$k = \dfrac{3.10 \times 10^{6}~N~m^{-2} \times \pi \times (0.00093)^{2}~m^{2}}{.027~m} = 3.11 \times 10^{2}~Kg~s^{-2}$

Part(b):

We know the amount of work done ( $W$ ) on the collagen is stored as a potential energy ( $U$ ) within it. Now, the amount of work done by the variable force that stretches the collagen can be written as

$W = \dfrac{1}{2}k~x^{2} = \dfrac{(\dfrac{F}{k})^{2}k}{2} = \dfrac{F^{2}}{2~k}...................................(IV)$

Substituting all the values, we can write

$W = \dfrac{(3.06 \times 10^{-2})^{2}~N^{2}}{2 \times 3.11 \times 10^{2}~Kg~s^{-2}} = 1.5 \times 10^{-6}~J$

3 0

3 years ago

Visible light transmitting through a certain medium.

Verizon [17]

I think its A: Translucent hope this helps if I'm wrong I'm sorry

8 0

3 years ago