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Allushta [10]
3 years ago
9

A copy machine makes 32 copies per minute. How long does it take to make 136 copies?

Mathematics
2 answers:
sleet_krkn [62]3 years ago
8 0
136 papers in total/32 papers per minutes=4.5 mins
Naya [18.7K]3 years ago
7 0

Answer: about 4 mins and 25 seconds.

Step-by-step explanation:

if u want it in mins then its 4

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find the sum of the area under the standard normal curve to the left of z = - 1.25 and the right of z = 1.25.
GREYUIT [131]

The standard normal curve is symmetric, so the area to the left of z = -1.25 is the same as that to the right of z = 1.25. Find one or the other and double your result.

To the left of 1.25: normalcdf(-1000, 1.25) = 0.1056, or 0.106. Double that; result is 0.212 (answer).

7 0
3 years ago
Rima and Eric have earned a total of 135 tokens to buy items at the school store. The ratio of the number of tokens that Rima ha
raketka [301]

Answer:

127

Sqep-by-step explanation:

135-8:7

3 0
3 years ago
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A starter motor used in a space vehicle has a high rate of reliability and was reputed to start on any given occasion with proba
GuDViN [60]

Answer:

0.095163

Step-by-step explanation:

given that a starter motor used in a space vehicle has a high rate of reliability and was reputed to start on any given occasion with probability .99999

Here we find that for any start, there are exactly two outcomes either success or failure.

Also each start is independent of the other since p = 0.99999 for succss is given constant.

Thus X no of successes is binomial with p = 0.99999 and n =10000

If Y is taken as failure then Y is binomial with p' = 0.00001 and n =10000

Required probability

= the probability of at least one failure in the next 10,000 starts

= 1-P(no failure in 10000 starts)

=1-(0.99999)^{10000} \\=0.095163

4 0
4 years ago
You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

mean = 15.58

the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

7 0
3 years ago
Maths<br> 1. 24÷ (-6)<br><br> 2. -15 ÷ 0.3<br><br> 3. -4 ÷ (-20)
Lesechka [4]

Answer:

hope it helps

Step-by-step explanation:

1) -72

2) -50

3) 0.2

8 0
3 years ago
Read 2 more answers
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