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Nana76 [90]
3 years ago
9

In a nuclear reactor, the control rods are: A.made of graphite B.used to keep the reactor cool C.used to absorb free neutrons D.

all of the above E.none of the above
Physics
2 answers:
algol133 years ago
4 0
I think its E. the control rods are used to control <span>the fission rate of uranium and plutonium. Hope this helps!! </span>
Anni [7]3 years ago
4 0
Hi!

The answer is E) none of the above, because control rods in a nuclear reactor is made of uranium

Hope this helped! Have a nice day!
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A basketball player of height 2.40 m is standing 2.60 m in front of a convex spherical mirror of radius of curvature 4.00 m. Det
IrinaVladis [17]

Answer:

The size of the image is 1.04 m.

Explanation:

Given that,

Height of object = 2.40 m

Distance of object = 2.60 m

Radius of curvature =4.00 m

Focal length f=\dfrac{R}{2}=\dfrac{4.00}{2}=2.00

We need to calculate the image distance

Using mirror formula

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{2.00}+\dfrac{1}{2.60}

\dfrac{1}{v}= \dfrac{23}{26}

v=1.13\ cm

We need to calculate the height of the image

Using formula of magnification

m=\dfrac{h'}{h}=-\dfrac{v}{u}

Put the value into the formula

\dfrac{h'}{2.40}=-\dfrac{1.13}{-2.60}

h'=\dfrac{1.13}{2.60}\times2.40

h'=1.04\ m

Hence, The size of the image is 1.04 m

8 0
3 years ago
A 21 g ball is shot from a spring gun whose spring has a force constant of 579 N/m. The spring can be compressed 1 cm. How high
vodka [1.7K]

Answer:

The answer  to the question is

The ball will go 0.14 meters high if the gun is aimed vertically

Explanation:

The energy in the spring → Energy, E = \frac{1}{2}kx^2

Where E = energy in the spring

k = Spring constant

x = Spring compression or stretch

Therefore E = \frac{1}{2} 579*0.01^2 = 0.02895 J

The spring energy is transferred  to the ball as kinetic energy based on the first law of thermodynamics which states that energy is neither created nor destroyed

Kinetic energy = KE = \frac{1}{2}mv^2

From which v = \sqrt{\frac{2*KE}{m} } = \sqrt{\frac{2*0.02895}{0.021} } = 1.66 m/s

from v² =u² - 2·a·S

Where v = final velocity = 0 m/s

u = initial velocity = 1.66 m/s

a = g = Acceleration due to gravity

S = height

Therefore 0 = 1.66² - 2×9.81×S

or S = 1.66² ÷ (2×9.81) = 0.14 m

7 0
3 years ago
Help please what law is happening in these pictures
Karolina [17]
Answer: boyles law I’m pretty sure
7 0
2 years ago
Shortly after receiving a traffic ticket for speeding, Fred made numerous comments about the road signs being inadequate and is
k0ka [10]

Answer:

External locus of control

Explanation:

External locus of control is an attitude people possess that makes them attribute their failures or successes to factors other than themselves. The opposite of this type of attitude is the Internal locus of control where the individuals take responsibility for the outcomes of their actions whether good or bad. One good thing about the external locus of control is that when the individuals with this characteristic record successes, they attribute it to others and this presents them as people with team spirit. However, when they record failures, they do not want to take the blame, but rather attribute it to others.

Fred exhibits an external locus of control because he attributed his speeding to other factors like the road signs and GPS instead of fully admitting that it was his fault.

7 0
3 years ago
True or False: The height from which cliff divers jump affects the velocity at which they will fall. Velocity is speed in a cert
Juli2301 [7.4K]

Answer:

the diver's speed is independent of the launch height.

Explanation:

For this exercise we must use Newton's second law

              fr - W = m a

the friction force has the general form

              fr = b v

Let's analyze this equation to find out what happens with the speed of the distant club.

When jumping, the initial speed is zero, so the friction force is zero and has an acceleration equal to the acceleration of gravity, as the speed increases the friction force increases decreasing the acceleration until it becomes zero, when it arrives at this value the velocity it has is called terminal velocity and this velocity remains fixed in relation to the trajectory.

             fr = W

             v = cte

The distance or time in which this equilibrium is reached is relatively fast, so the diver's speed is independent of the launch height.

8 0
2 years ago
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