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mel-nik [20]
3 years ago
5

A mule pulls a cart of milk 10 meters with a force of 50 Newton's.Calculate the work done by a mule

Physics
2 answers:
san4es73 [151]3 years ago
8 0

Work = Force x Distance

Assuming that this work is being done parallel to the displacement that is, but under that assumption:

W = (50)(10)

W = 500 J

Alex73 [517]3 years ago
4 0

Answer: W = (50)(10)

Explanation:

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Magnetic stripes on the sea floor

Explanation:

The observation of magnetic stripes patterns at the region of the Mid-Atlantic Ridge galvanized the evidence that sea floor spreading has been on for several millions of years.

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3 years ago
Vocabulary word for the total amount of charge in a closed system remains constant
Usimov [2.4K]

Answer:

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7 0
3 years ago
If the speed of light in a substance is 2.26 x 10^8 m/s, what is the index of refraction of that substance?
vladimir1956 [14]

Answer:

1.33

Explanation:

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speed of light in medium, v = 2.26 x 10^8 m/s

The refractive index of the medium is given by

μ = speed of light in vacuum / speed of light in medium

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Read 2 more answers
A mass of 0.56 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic mot
NemiM [27]

Answer:

(a) 0.42 m

(b) 20.16 N/m

(c) - 0.42 m

(d) - 0.21 m

(e) 17.3 s

Solution:

As per the question:

Mass, m = 0.56 kg

x(t) = (0.42 m)cos[cos(6 rad/s)t]

Now,

The general eqn is:

x(t) = Acos\omega t

where

A = Amplitude

\omega = angular frequency

t = time

Now, on comparing the given eqn with the general eqn:

(a) The amplitude of oscillation:

A = 0.42 m

(b) Spring constant k is given by:

\omega = \sqrt{k}{m}

\omega^{2} = \frac{k}{m}

Thus

k = m\omega^{2} = 0.56\times 6^{2} = 20.16\ N/m

(c) Position after one half period:

x(t) = 0.42cos\pi = - 0.42\ m

(d) After one third of the period:

x(t) = 0.42cos(\frac{2\pi}{3}) = - 0.21\ m

(e) Time taken to get at x = - 0.10 m:

-0.10 = 0.42cos6t

6t = co^{- 1} \frac{- 0.10}{0.42}

t = 17.3 s

7 0
3 years ago
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