The gravitational potential energy referred to the ground level is given by

where m is the mass of the object,

is the gravitational acceleration and h is the height of the object with respect to the ground.
Therefore in our problem the potential energy is
Answer:
The initial speed of the block is 1.09 m/s
Explanation:
Given;
mass of block, m = 1.7 kg
force constant of the spring, k = 955 N/m
compression of the spring, x = 4.6 cm = 0.046 m
From principle of conservation of energy
kinetic energy of the block = elastic potential energy of the spring
¹/₂mv² = ¹/₂kx²
mv² = kx²

where;
v is the initial speed of the block
x is the compression of the spring

Therefore, the initial speed of the block is 1.09 m/s
<h3>
Answer:</h3>
<h3>
Explanation:</h3>
_______________
S=3 m²
F=900 N
_______________
p - ?
_______________
p=F/S=900 N / 3 m² = 300 Pa