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tatuchka [14]
3 years ago
6

Which is equivalent to 243 2/5 ? 3 6 9 12

Mathematics
2 answers:
Vlada [557]3 years ago
5 0

Answer:

The answer is 9

Step-by-step explanation:

we have

(243)^{\frac{2}{5}}

we know that

a^{\frac{n}{m}}=\sqrt[m]{a^{n}}

so

(243)^{\frac{2}{5}}=\sqrt[5]{243^{2}}

Remember that

243=3^{5}

Substitute

\sqrt[5]{243^{2}}=\sqrt[5]{(3^{5})^{2}}\\ \\= \sqrt[5]{(3^{10})}\\ \\=3^{\frac{10}{5}}\\ \\= 3^{2} \\ \\=9

NeTakaya3 years ago
3 0
9 Good luckkkkkkkkkkkkkkkkkkkkkkkkkkkkk

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Multiply using FOIL or Table method (x + 4) (x + 5)
mylen [45]

Answer:

{x}^{2}  + 9x + 20

Step-by-step explanation:

1) Use FOIL method: (a + b) (c + d) = ac + ad + bc + bd.

{x}^{2}  + 5x + 4x + 20

2) Collect like terms.

{x}^{2}  + (5x + 4x) + 20

3) Simplify.

{x}^{2}  + 9x + 20

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><u>x</u><u>²</u><u> </u><u>+</u><u> </u><u>9x</u><u> </u><u>+</u><u> </u><u>20</u>.

5 0
3 years ago
Please help and show work!!
Paladinen [302]

B. Because 20 is greter than 18.

6 0
3 years ago
Read 2 more answers
Kent thinks that x+x and x2 are equivalent expressions because they each have a value of 4 when x=2. Which statement best demons
timofeeve [1]
Kevin is incorrect because x+x is adding two numbers, but x^2 is multiply.
3 0
3 years ago
During the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this
alex41 [277]

Answer:

Step-by-step explanation:

Given that during  the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this period, P(t) remained close to the solution of the initial value problem.

\frac{dP}{dt} =0.03135P =0.0001489P^2, P(0) = 3.9

a) 1930 population is the population at time t = 40 years taking base year as 40

We can solve the differential equation using separation of variables

\frac{dP}{0.03135P – 0.0001489P^2 } =dt\\\frac{dP}{-P(0.03135 – 0.0001489P } =dt

Resolve into partial fractions

\frac{31.8979}{P} -\frac{0.00474}{0.0001489P-0.03135}

Integrate to get

ln P -0.00474/0.0001489  (ln (0.0001489P-0.03135) = t+C

ln P -31.833  (ln (0.0001489P-0.03135) =t+C

\frac{P}{( ( (0.0001489P-0.03135)^{31.833}  } =Ae^t

Limiting population would be infinity.

6 0
4 years ago
the constant value which is repeatedly added to each term in an arithmetic sequence to obtain the next term​
Mariulka [41]

Answer:

<h2>This value is called the common difference</h2>

Step-by-step explanation:

The common difference is the constant value which is repeatedly added to each term in an arithmetic sequence to obtain the next term​, it is basically the difference between consecutive numbers

To find the common difference we can subtract the previous term from the first time or the second to the last term from the last term, the idea of finding the common difference is basically subtracting the previous term form the subsequent term.

7 0
4 years ago
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