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Finger [1]
3 years ago
4

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = - 16t^2 + 57

6t. After how many seconds does the projectile take to reach its maximum height? Show your work for full credit.
Physics
1 answer:
never [62]3 years ago
5 0
The time required for the maximum height to be attained is calculated by differentiating the given equation and equating the derivative to zero. 
                                    h(t) = -16t² + 576t
                            dh(t) / dt = 0 = (-16)(2)t + 576
The value of t from the equation is 18. Thus, after 18 seconds the projectile reaches its maximum height. 
                                   
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3 years ago
The energy stored by any pair of positive charges is inversely proportional to the distance between them, and directly proportio
denpristay [2]

Answer:

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Explanation:

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in this case we have three charges of equal magnitude

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3 years ago
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Answer

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slamgirl [31]

Answer:

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⇒    =(1.097 \ N/m)\hat{j}

8 0
3 years ago
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