Answer:
measured in GHz?
Explanation:
im not sure what the context is it depends on what your lesson is on
 
        
             
        
        
        
Answer:
total distance = 1868.478 m
Explanation:
given data 
accelerate = 1.68 m/s²
time = 14.2 s
constant time = 68 s
speed = 3.70 m/s²
to find out
total distance
solution
we know train start at rest so final velocity will be after 14 .2 s is
velocity final = acceleration × time      ..............1
final velocity = 1.68 × 14.2 
final velocity = 23.856 m/s²
and for stop train we need time that is 
final velocity = u + at
23.856 = 0 + 3.70(t)
t = 6.44 s
and 
distance = ut + 1/2 × at²     ...........2 
here u is initial velocity and t is time for 14.2 sec
distance 1 = 0 + 1/2 × 1.68 (14.2)² 
distance 1 = 169.37 m
and 
distance for 68 sec
distance 2= final velocity × time
distance 2= 23.856 × 68 
distance 2 = 1622.208 m
and 
distance for 6.44 sec
distance 3 = ut + 1/2 × at²
distance 3 = 23.856(6.44) - 0.5 (3.70) (6.44)²
distance 3 = 76.90 m
so 
total distance = distance 1 + distance 2 + distance 3 
total distance = 169.37 + 1622.208 + 76.90
total distance = 1868.478 m
 
        
                    
             
        
        
        
<span>B. because they cannot make light rays converge</span>