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The statement "<span>A standing wave is one which travels through space indefinitely." is false.</span>
If we increase the length of the resistor, resistance will also increase and vice-versa.
It is given that in a wire simulation, we have to adjust only the length of the resistor.
It required to find the effect on resistor when adjust only the length of the resistor.
<h2>What happens to resistor when adjust only the length of the resistor?</h2>
As we know that the length is directly proportional to the resistance of the wire that means is we increase the size or length of the wire then it also increase the resistance present in the wire. On the other hand if we decrease the length of the wire, it will decrease the resistance. This can be represented as:
Resistance = resistivity × length/area
This is also because there is more collision of the flowing electrons in the wire to the metal ions present there.
Thus if we increase the length of the resistor, resistance will also increase and vice-versa.
Learn more about the resistance here:
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Answer:
5.4 cm³
Explanation:
Ideal gas law:
PV = nRT
where P is absolute pressure, V is volume, n is number of moles, R is ideal gas constant, and T is absolute temperature.
Since n and R are constant, we can say:
PV / T = constant
At the bottom of the lake, the pressure is:
P = ρgh + Patm
P = (1000 kg/m³) (9.8 m/s²) (40.5 m) + 101,325 Pa
P = 498,225 Pa
And the temperature is:
T = 2.3 + 273.15 K
T = 275.45 K
At the top of the lake, the pressure is:
P = Patm
P = 101,325 Pa
And the temperature is:
T = 28.1 + 273.15 K
T = 301.25 K
Therefore:
PV / T = PV / T
(498225 Pa) (1.00 cm³) / (275.45 K) = (101325 Pa) V / (301.25 K)
V = 5.4 cm³
Answer:
When you throw a ball against a wall or drop it onto the floor, you notice that it bounces back up again. In the same way, when the ball hits the floor and gets squished, it pushes back against the floor to try to make itself round again.
Explanation:
