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mr_godi [17]
3 years ago
8

Write the rate law for the reaction 2A + B → C if the reaction

Chemistry
1 answer:
konstantin123 [22]3 years ago
4 0

Answer:

1.   R=k[A]^1[B]^2

2.  R=k[B]^1

3.  R=k[A]^0[B]^0=k

4.  R=k[A]^1[B]^{-1}

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

(1) is second order in B and overall third order.

2A + B → C

Order of the reaction = sum of stoichiometric coefficient

= x + 2 = 3

x = 1

Rate of the reaction =R

R=k[A]^1[B]^2

(2) is zero order in A and first order in B.

2A + B → C

Rate of the reaction =R

R=k[A]^0[B]^1=k[B]^1

Order of the reaction = sum of stoichiometric coefficient

= 0 + 1 = 1

(3) is zero order in both A and B .

2A + B → C

Order of the reaction = sum of stoichiometric coefficient

= 0 + 0 = 0

Rate of the reaction =R

R=k[A]^0[B]^0=k

(4) is first order in A and overall zero order.

2A + B → C

Order of the reaction = sum of stoichiometric coefficient

= 1 + x = 0

x = -1

Rate of the reaction = R

R=k[A]^1[B]^{-1}

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