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wlad13 [49]
2 years ago
11

Which statement correctly compares the masses of subatomic particles in an atom such as carbon?

Chemistry
1 answer:
iogann1982 [59]2 years ago
5 0

Answer:

C- A proton has about the same mass as a neutron .

Explanation:

In an atom such as a carbon atom, the masses of the proton and neutrons are the same.

The mass of the electrons is very negligible.

  • Protons are the positively charged particles in an atom
  • Neutrons do not carry any charges
  • Both protons and neutrons have similar masses.
  • They contribute the bulk of the mass of the atom.
  • The electrons carry negative charges and they have negligible masses.

The mass of protons and neutrons are similar.

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Draw the structures of methyl oleate and propylene glycol. Which one is more polar, and how can you tell
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2 years ago
Which of the following is not an example of a polymer?
Nady [450]
I believe the correct answer from the choices listed above is the third option. It is amino acid that is not an example of a polymer. It <span> is a large molecule, or macromolecule, composed of many repeated subunits. Hope this answers the question.</span>
7 0
3 years ago
How man grams of cl2 are consumed to produce 12.0 g of KCl
Korvikt [17]

Answer:

5.71 g

Explanation:

Step 1: Write the balanced equation

2 K + Cl₂ ⇒ 2 KCl

Step 2: Calculate the moles corresponding to 12.0 g of KCl

The molar mass of KCl is 74.55 g/mol.

12.0 g × 1 mol/74.55 g = 0.161 mol

Step 3: Calculate the moles of Cl₂ needed to produce 0.161 moles of KCl

The molar ratio of Cl₂ to KCl is 1:2. The moles of Cl₂ needed are 1/2 × 0.161 mol = 0.0805 mol

Step 4: Calculate the mass corresponding to 0.0805 moles of Cl₂

The molar mass of Cl₂ is 70.91 g/mol.

0.0805 mol × 70.91 g/mol = 5.71 g

8 0
2 years ago
What is the empirical formula of a compound with a percent composition of 22.5% Phosphorous and 77.5% Chlorine?
sashaice [31]

Answer:

\boxed {\boxed {\sf PCl_3}}

Explanation:

We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.

We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.

  • 22.5 g P
  • 77.5 g Cl

Next, convert these masses to moles, using the molar masses found on the Periodic Table.

  • P: 30.974 g/mol
  • Cl: 35.45 g/mol

Use the molar masses as ratios and multiply by the number of grams. 22.5 \ g \ P  * \frac {1 \ mol \ P }{30.974 \ g \ P}= \frac {22.5 \ mol \ P }{ 30.974} = 0.7264157035 \ mol \ P

77.5 \ g \ Cl  * \frac {1 \ mol \ Cl }{35.45 \ g \ Cl}= \frac {77.5 \ mol \ Cl }{ 35.45} \ =2.186177715 \ mol \ Cl

Divide both of the moles by the smallest number of moles to find the mole ratio.

\frac {0.7264157035} {0.7264157035} = 1

\frac {2.186177715}{0.7264157035}=3.009540824 \approx 3

The mole ratio is about 1 P: 3 Cl, so the empirical formula is written as:<u> PCl₃</u>

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2 years ago
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