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nadezda [96]
3 years ago
7

Although the evidence is weak, there has been concern in recent years over possible health effects from the magnetic fields gene

rated by transmission lines. A typical high-voltage transmission line is 20 m off the ground and carries a current of 200 A . Part A Estimate the magnetic field strength on the ground underneath such a line. Express your answer in microtesla. B B = nothing μT SubmitRequest Answer Part B What percentage of the earth’s magnetic field does this represent? (Assume that magnetic field strength at the surface of the earth is 5× 10 −5 T ) Express your answer in percent. B tl B Earth B t l B E a r t h = nothing % SubmitRequest Answer Provide Feedback Next
Physics
1 answer:
Rzqust [24]3 years ago
5 0

A) 2.0\cdot 10^{-6} T

The magnetic field strength around a current-carrying wire is given by the formula

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0 = 1.257 \cdot 10^{-6} H/m is the vacuum permeability

I is the current in the wire

r is the radial distance from the wire

In this problem, we have

I = 200 A is the current in the wire

and we want to calculate the magnetic field strength at a distance of

r = 20 m

from the wire, so:

B=\frac{(1.257\cdot 10^{-6})(200)}{2\pi (20)}=2.0\cdot 10^{-6} T

B) 4 %

The magnetic field strength at the surface of the Earth is

B_e = 5\cdot 10^{-5} T

While the strength of the magnetic field generated by the wire at ground level is

B=2.0\cdot 10^{-6} T

Therefore, in percentage, it is:

\frac{B}{B_e}=\frac{2.0\cdot 10^{-6}}{5\cdot 10^{-5}}\cdot 100 = 0.04 \cdot 100 = 4 \%

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A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent
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The wavelengths of the constituent travelling waves CANNOT be 400 cm.

The given parameters:

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<em />

The wavelengths of the constituent travelling waves is calculated as follows;

L = \frac{n \lambda}{2} \\\\n\lambda = 2L\\\\\lambda = \frac{2L}{n}

for first mode: n = 1

\lambda = \frac{2\times 100 \ cm}{1} \\\\\lambda = 200 \ cm

for second mode: n = 2

\lambda = \frac{2L}{2} = L = 100 \ cm

For the third mode: n = 3

\lambda = \frac{2L}{3} \\\\\lambda = \frac{2 \times 100}{3} = 67 \ cm

For fourth mode: n = 4

\lambda = \frac{2L}{4} \\\\\lambda = \frac{2 \times 100}{4} = 50  \ cm

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.

The complete question is below:

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:

A. 400 cm

B. 200 cm

C. 100 cm

D. 67 cm

E. 50 cm

Learn more about wavelengths of travelling waves here: brainly.com/question/19249186

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