Answer:
a)Distance traveled during the first second = 4.905 m.
b)Final velocity at which the object hits the ground = 38.36 m/s
c)Distance traveled during the last second of motion before hitting the ground = 33.45 m
Explanation:
a) We have equation of motion
S = ut + 0.5at²
Here u = 0, and a = g
S = 0.5gt²
Distance traveled during the first second ( t =1 )
S = 0.5 x 9.81 x 1² = 4.905 m
Distance traveled during the first second = 4.905 m.
b) We have equation of motion
v² = u² + 2as
Here u = 0, s= 75 m and a = g
v² = 0² + 2 x g x 75 = 150 x 9.81
v = 38.36 m/s
Final velocity at which the object hits the ground = 38.36 m/s
c) We have S = 0.5gt²
75 = 0.5 x 9.81 x t²
t = 3.91 s
We need to find distance traveled last second
That is
S = 0.5 x 9.81 x 3.91² - 0.5 x 9.81 x 2.91² = 33.45 m
Distance traveled during the last second of motion before hitting the ground = 33.45 m
Average acceleration of the baseball: 
Explanation:
Since the motion of the baseball is a uniformly accelerated motion, we can use the following suvat equation:
where
u is the initial velocity
v is the final velocity
a is the acceleration
s is the displacement of the object
For the baseball in this problem, we have:
u = 2.2 m/s is the initial velocity
v = 0 is the final velocity (it comes to a stop)
s = 24 mm = 0.024 m is the displacement of the ball while decelerating
Therefore, we can solve for a to find the acceleration:
where the negative sign means the baseball is slowing down.
Learn more about acceleration:
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Answer:
The only such elements are the Noble Gases (He, Ne, Ar, Kr, Xe, Rn)
(that is helium, neon, argon, krypton, xenon and radon)
Term: Monoatomic
Explanation:
First overtone of open organ pipe is given as
first overtone of closed organ pipe is given as
now they are in unison so we will have
so end correction of both pipes is e = 1 cm
Answer:
Kinetic Energy:120 x 15=1800
Explanation:
