A 49.48-mL sample of an ammonia solution is analyzed by titration with HCl. It took 38.73 mL of 0.0952 M HCl to titrate the ammo
1 answer:
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Answer: 0.172 M
Explanation:
a) To calculate theconcentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
b) To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
The concentration of the phosphoric acid solution is 1.172 M
Answer : The density of an object is 0.93 g/mL
Explanation : Given,
Mass of an object = 3.8 g
Initial volume = 4.5 mL
Final volume = 8.6 mL
First we have to calculate the volume of an object.
Volume of an object = Final volume - Initial volume
Volume of an object = 8.6 mL - 4.5 mL
Volume of an object = 4.1 mL
Now we have to calculate the density of an object.
Formula used:
Now putting all the given values in this formula, we get:
Therefore, the density of an object is 0.93 g/mL