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olga55 [171]
2 years ago
8

How many half-lives are required for the concentration of reactant to decrease to 12. 5% of its original value?.

Chemistry
1 answer:
Tcecarenko [31]2 years ago
5 0

Answer:

Three half-lives

Explanation:

12.5% is one-eighth. One eighth is the cube of one half, so it would take three half-lives to reduce a reactant's concentration to 12.5%

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Answer: waning gibbous

Explanation:

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3 years ago
Write a word or phrase begining with each letter of the word CHANGE that describes changed you have observed in everyday objects
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6 0
3 years ago
Mr. Holmes is busy making a paper mache volcano that he is sure is going to win the national science fair contest. He only has r
AnnyKZ [126]

Answer:

Bottle 2 shows the vinegar has a molarity of 2M acetic acid

Explanation:

2M of acetic acid has higher concentration of acetic acid as compared to other vinegar. In 2M of acetic acid is equals to 120 gram of acetic acid in 500 ml of water which is quiet higher than other concentration of acetic acid in vinegar which is 4%. So Mr. Holmes has to use 2M of acetic acid which will produced high intense eruption in the volcano and win the national science fair contest.

7 0
3 years ago
Why was nutmeg also called the spice of madness
lapo4ka [179]
It was called the “spice of madness” because it had an hallucinogenic property.
8 0
3 years ago
Which of the following has the most atoms per mole?
BabaBlast [244]

Answer:

e) Na₃PO₄

Explanation:

a) BaSO₄

1 mole of BaSO ₄ = 6.022×10²³ molecules

1 mole of BaSO ₄ contain 1 atom of Ba one atom of S and four atoms of O.

Total number of atoms = 6 atoms

6.022×10²³ × 6 atoms = 36.132 ×10²³ atoms

b) NaNO₂

1 mole of NaNO₂= 6.022×10²³ molecules

1 mole of NaNO₂ contain 1 atom of Na one atom of N and two atoms of O.

Total number of atoms = 4 atoms

6.022×10²³ × 4 atoms = 24.088 ×10²³ atoms

c)KMnO₄

1 mole of KMnO₄ = 6.022×10²³ molecules

1 mole of KMnO₄ contain 1 atom of K one atom of Mn and four atoms of O.

Total number of atoms = 6 atoms

6.022×10²³ × 6 atoms = 36.132 ×10²³ atoms

d) KCl

1 mole of KCl = 6.022×10²³ molecules

1 mole of KCl contain 1 atom of K one atom of Cl.

Total number of atoms = 2 atoms

6.022×10²³ × 2 atoms = 12.044 ×10²³ atoms

e) Na₃PO₄

1 mole of Na₃PO₄ = 6.022×10²³ molecules

1 mole of Na₃PO₄ contain 3 atom of Na one atom of P and four atoms of O.

Total number of atoms = 8 atoms

6.022×10²³ × 8 atoms = 48.176×10²³ atoms

3 0
3 years ago
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