True. they would have to be naturally occurring in the earth’s system.
1) Molar mass C8H9NO2
Element Atomic mass # of atoms mass
g/mol g
C 12 8 12*8 = 96
H 1 9 1*9 = 9
N 14 1 14*1 = 14
O 16 2 16*2 = 32
molar mass = 96 + 9 + 14 + 32 = 151 g/mol
2) Number of mols in a tablet
# of moles = mass / molar mass = 0.500 g / 151 g/mol = 0.003311 moles
3) 3 doses * 2 tablets * 0.003311 moles / tablet = 0.020 moles
Answer:
3.3765 Mol O2
Explanation:
There is no work for this problem
Answer:
The given compound cannot be cocaine.
Explanation:
The chemist can comment on the nature of compound being cocaine or not from the depression in freezing point.
Depression in freezing point of is related to molality as:
Depression in freezing point = Kf X molality
Where
Kf = cryoscopic constant = 4.90°C/m
depression in freezing point = normal freezing point - freezing point of solution
depression in freezing point = 5.5-3.9 = 1.6°C
1.6°C = 4.90 X molality

we know that:

therefore
moles = 0.327X0.008 = 0.00261 mol


The molar mass of cocaine is 303.353
So the given compound cannot be cocaine.