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liubo4ka [24]
3 years ago
10

When did ernest rutherford contribute to the atomic theory?

Chemistry
1 answer:
charle [14.2K]3 years ago
6 0
In 1911, Rutherford performed experiment to determine the structure on atom
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Natural resources do not come from outside the Earth's system.<br> O True<br> O False
Ne4ueva [31]
True. they would have to be naturally occurring in the earth’s system.
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2 years ago
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Acetaminophen (C8H9NO2) is the active ingredient in many nonprescription pain relievers. Each tablet contains 500 mg of acetamin
ohaa [14]
1) Molar mass C8H9NO2

Element    Atomic mass    # of atoms   mass
                       g/mol                                  g
C               12                         8               12*8 = 96
H                 1                         9                1*9 =    9
N               14                         1               14*1 = 14
O               16                        2                16*2 = 32

                              molar mass =   96 + 9 + 14 + 32 = 151 g/mol

2) Number of mols in a tablet

# of moles = mass / molar mass = 0.500 g / 151 g/mol = 0.003311 moles

3) 3 doses * 2 tablets * 0.003311 moles / tablet = 0.020 moles
7 0
3 years ago
A Question 2 (2 points) Retake question
Ksivusya [100]

Answer:

3.3765 Mol O2

Explanation:

There is no work for this problem

3 0
3 years ago
A forensic chemist is given a white powder for analysis. She dissolves 0.50 g of the substance in 8.0 g of benzene. The solution
Sholpan [36]

Answer:

The given compound cannot be cocaine.

Explanation:

The chemist can comment on the nature of compound being cocaine or not from the depression in freezing point.

Depression in freezing point of is related to molality as:

Depression in freezing point = Kf X molality

Where

Kf = cryoscopic constant = 4.90°C/m

depression in freezing point = normal freezing point - freezing point of solution

depression in freezing point = 5.5-3.9 = 1.6°C

1.6°C = 4.90 X molality

molality=\frac{1.6}{4.90} = 0.327 m

we know that:

molality=\frac{moles}{mass of solvent(kg)}=\frac{moles}{0.008kg}

therefore

moles = 0.327X0.008 = 0.00261 mol

moles=\frac{mass}{molarmass}

molarmass=\frac{mass}{moles}=\frac{0.50}{0.00261}= 191.57g/mol

The molar mass of cocaine is 303.353

So the given compound cannot be cocaine.

3 0
3 years ago
Please help. 1.600x10^8 / 8.000x10^11
sweet-ann [11.9K]

Answer:

2x10^-4 = 2E-4

Explanation:

3 0
2 years ago
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