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Deffense [45]
3 years ago
10

A home in small town in Texas is currently worth $344,000. It is expected to grow by 5% per year over the next several years.

Mathematics
1 answer:
Kitty [74]3 years ago
6 0

Answer:

Part A: The value of the house (y) after x years:

y = 344000 x (1 + 5/100)^x

Part B: Approximate value of the house after 10 years:

(Using the formula in part A)

V = 344000 x (1 + 5/100)^10 = 560339.8 $

Hope this helps!

:)

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What are two whole numbers that √111 fall between?
lana66690 [7]

Answer:

I believe it would be 9 & 10. 9^2 is 81 and 10^2 is 100 which are numbers that fall in between √111.

Step-by-step explanation:

3 0
3 years ago
You eat 2/3 of your pizza and you have 4 slices leftover. How many slices did you originally order? Write and solve an equation
avanturin [10]

Answer:

12

Step-by-step explanation:

4 × 3 = 12

3/3 = 12

2/3 = 8

1/3 = 4

8 slices were eaten and 4 are left, and if you add 8 + 4 or you multiply the 3 × 4, you get 12. There were originally 12 slices.

5 0
2 years ago
If EG = 3y - 10 and ET = 2y, find the value of y In parallelogram FGHI.<br> 1<br> Find Value of y.
Ksenya-84 [330]
<h3>Answer:  y = 10</h3>

=====================================

Work Shown:

EI = EG

3y-10 = 2y

3y-10-2y = 0

y-10 = 0

y = 0+10

y = 10

Note how if y = 10, then

  • EI = 3y-10 = 3*10-10 = 20
  • EG = 2y = 2*10 = 20

Both EI and EG are 20 units long when y = 10. This confirms the answer.

6 0
3 years ago
92% of what number is 115 ?
Andrej [43]
\frac { 92 }{ 100 } \cdot n=115\\ \\ 92n=11,500\\ \\ n=\frac { 11,500 }{ 92 } \\ \\ \therefore \quad n=125
7 0
3 years ago
A study showed that 14 of 180 publicly traded business services companies failed a test for compliance with Sarbanes-Oxley requi
Vika [28.1K]

Answer:

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 180, \pi = \frac{14}{180} = 0.0778

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 - 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.0387

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 + 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.1169

The 95% confidence interval for the overall noncompliance proportion is (0.0387, 0.1169).

4 0
3 years ago
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