Answer:
21 + 5 is the the same thing.
Step-by-step explanation:
we have

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Complete the square. Remember to balance the equation by adding the same constants to each side



Rewrite as perfect squares


therefore
<u>the answer is</u>


Answer:
Yes, it's also true about the confidence interval method.
Step-by-step explanation:
The confidence interval includes all the null hypothesis values for the population mean that would be accepted by the hypothesis test at the significance level of 5%. Now, it means this assumes a two-sided alternative.
Now, when testing claims about
population proportions, the critical method and the P-value method are equivalent due to the fact that they always produce the same result. Similarly, a conclusion based on a confidence interval estimate will be the same as a conclusion based on a hypothesis test.
So, Yes the confidence interval method and the P-value or critical methods will always lead to the same conclusion when the tested parameter is the standard deviation.
Answer:
A² - 6A + 11 I = ![\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given the matrix
![A=\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D)
Calculate A² - 6A + 11 I
![A^2 = A*A= \left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] *\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] = \left[\begin{array}{ccc}2*2-3*1&2*3+3*4\\-1*2-4*1&-1*3+4*4\end{array}\right] =\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right]](https://tex.z-dn.net/?f=A%5E2%20%3D%20A%2AA%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%2A2-3%2A1%262%2A3%2B3%2A4%5C%5C-1%2A2-4%2A1%26-1%2A3%2B4%2A4%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2618%5C%5C-6%2613%5Cend%7Barray%7D%5Cright%5D)
![6A=6*\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] =\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right]](https://tex.z-dn.net/?f=6A%3D6%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%5C%5C-1%264%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%2618%5C%5C-6%2624%5Cend%7Barray%7D%5Cright%5D)
![11 I = 11 * \left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =\left[\begin{array}{ccc}11&0\\0&11\end{array}\right]](https://tex.z-dn.net/?f=11%20I%20%3D%2011%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%260%5C%5C0%2611%5Cend%7Barray%7D%5Cright%5D)
∴ A² - 6A + 11 I = ![\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right] -\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right] +\left[\begin{array}{ccc}11&0\\0&11\end{array}\right] =\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2618%5C%5C-6%2613%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%2618%5C%5C-6%2624%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%260%5C%5C0%2611%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)