We can break down the number 6647 into:
6647=6000+600+40+7
The first 6 in the number is in the thousands place (6,000), and the second 6 is in the hundreds place (600).
The first 6 is 10 times greater than the second one.
Down three and over left four so something like (-3, -4) im pretty sure
If you add the numbers 57 and 59 together you get 116
Option A is correct as if we solve the equation We will find that the above equation can be compared to the standard quadratic equation i.e ax^2+bx+c=0
Step-by-step explanation:
where is the question??
