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2 years ago

What is the domain of y=cot x?

Mathematics

1 answer:

MissTica2 years ago

5 0

We have to find the domain of y = cotx

We know that cotx = cos x / sinx

And also when sinx becomes zero cotx becomes undefined

And again we know that value of cosx and sinx can be between -1 to 1

But value of cotx can lie in between -∞ to +∞

Just for example cot30 is cos30 / sin30

= √3/2/1/2 = √3

Therefore domain of cotx is x

x ∈ R , x ≠ πn for any integer n

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Estimate the sum of the decimal below by rounding to the nearest whole number.

Marizza181 [45]

The non-rounded sum is 15.579, so you’d round up to 16 since 5 and up rounds up. Hope this helps<3

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2 years ago

Why do you subtract exponents when dividing powers with the same base?

Anastasy [175]

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3 years ago

Simplify:- for y. 2x + 3 y/4 = 5

Fudgin [204]

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3 years ago

A leprechaun places a magic penny under a girls pillow. The next night there are 2 magic pennies under her pillow. The following

kiruha [24]

Answer:

After 47 days she will have more than 90 trillion pennies.

Step-by-step explanation:

At the beginning there was 1 penny. At the second day the amount of pennies under the pillow became 2.

The amount of pennies doubled each day. So the series is,

$1,2,4,8,16,32,.....$

This series is in geometric progression.

As the pennies from each of the previous days are not being stored away until more pennies magically appear so the sum of series will be,

$S_n=\dfrac{a(r^n-1)}{r-1}$

where,

a = initial term = 1,

r = common ratio = 2,

As we have find the number of days that would elapse before she has a total of more than 90 trillion, so

$\Rightarrow 90\times 10^{12}\le \dfrac{1(2^n-1)}{2-1}$

$\Rightarrow 90\times 10^{12}\le \dfrac{2^n-1}{1}$

$\Rightarrow 90\times 10^{12}\le 2^n-1$

$\Rightarrow 2^n\ge 90\times 10^{12}+1$

$\Rightarrow \log 2^n\ge \log (90\times 10^{12}+1)$

$\Rightarrow n\times \log 2\ge \log (90\times 10^{12}+1)$

$\Rightarrow n \ge \dfrac{\log (90\times 10^{12}+1)}{\log 2}$

$\Rightarrow n \ge 46.4$

$\Rightarrow n\approx 47$

8 0

2 years ago

Inverse function of f(x)=e^(2x-1)

Len [333]

f(x) = e²ˣ⁻¹
f⁻¹(x) = ln(2x - 1)

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2 years ago