Answer:

Explanation:
We are given that a parallel- plate capacitor is charged to a potential difference V and then disconnected from the voltage source.
1 m =100 cm
Surface area =S=


We have to find the charge Q on the positive plates of the capacitor.
V=Initial voltage between plates
d=Initial distance between plates
Initial Capacitance of capacitor

Capacitance of capacitor after moving plates


Potential difference between plates after moving








Hence, the charge on positive plate of capacitor=
Answer:
2 x 10^-8
Explanation:
the formula of wavelength is
the speed divided by frequency
so you have the speed given = 3.0x10^8m/s
and frequency = 1.5×10^16 Hz
so wavelength = 3.0x10^8m/s / 1.5x10^16 Hz
Answer:
<u>So the correct answer is letter e)</u>
Explanation:
The electric field of an infinite yz-plane with a uniform surface charge density (σ) is given by:

Where ε₀ is the electric permitivity.
<u>As we see, this electric field does not depend on distance, so the correct answer is letter e)</u>
I hope it helps you!
Great equation: distance = rate*time
So, distance run = 4.82 meters/second * 1.98 seconds = 9.5436 meters (round according to whatever the problem specifies, usually to the tenths or hundredths is sufficient).
This makes sense if you think about it since you are multiplying seconds with meters over seconds. The seconds cancel out, leaving you only the meters.
Answer:
P-value of the test statistic is 2.499
Explanation:
given data:
size sample is 24
sample mean is 414 gm
standard deviation is 15
Null hypotheis is


level of significance is 0.01
from test statics

degree od freedom is = n -1
df = 24 -1 = 13

t = -1.959
from t table critical value of t at 0.1 significane level and 23 degree of freedom is 2.499