Answer:
a. 0.947 m/s^2
b. 1304.54 N
c. 0.0966
Explanation:
mass of car = 13500 N = 13500/9.8 = 1377.55 kg
velocity = 50 km/h = 50,000 m/h = 13.9 m/s
raidus = 204 m
a. centripetal acceleartion = v^2/r = 13.9^2/204 = 0.947 m/s^2
b. centripetal force = m*centripetal acceleration = 1377.55 * 0.947 = 1304.54 N
c. In order for the car to round the curve safely, static friction = centripetal force
static friction = coefficient of friction (mu) * mg = mu* 1377.55*9.8 = 13500mu
13500mu = 1304.54
mu = 1304.54/13500 = 0.0966
C. The canoe's path will be a diagonal line from northeast to southwest.
Explanation:
We can solve this problem by using vector addition rules.
In fact, we know that:
- The velocity of the canoe has a component in the south direction, due to the velocity of the river which points towards south
- The canoe itself is trying to go from the eastern shore towards the western shore --> this means that the canoe has also a component of the velocity in the west direction
This means that the resultant velocity of the canoe must be in a direction intermediate between the directions of its two components: therefore, in the southwest direction.
Therefore, this means that
C. The canoe's path will be a diagonal line from northeast to southwest.
Learn more about vector addition:
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