The answer is C 8.87*10^4 m/s (it shouldn't be m/s^2 though as velocity is in m/s)
Since you know the acceleration is 12 m/s^2, the initial velocity is 2.39*10^4 m/s and the time (you have to convert to seconds) is 5400 seconds, then you can use the equation
v = vo + at
When you plug in the values you get
v = 2.39*10^4 + 5400*12 . so v = 8.87*10^4 m/s. C is your answer.
Answer:
Explanation:
Given that,
Mass of the thin hoop
M = 2kg
Radius of the hoop
R = 0.6m
Moment of inertial of a hoop is
I = MR²
I = 2 × 0.6²
I = 0.72 kgm²
Period of a physical pendulum of small amplitude is given by
T = 2π √(I / Mgd)
Where,
T is the period in seconds
I is the moment of inertia in kgm²
I = 0.72 kgm²
M is the mass of the hoop
M = 2kg
g is the acceleration due to gravity
g = 9.8m/s²
d is the distance from rotational axis to center of of gravity
Therefore, d = r = 0.6m
Then, applying the formula
T = 2π √ (I / MgR)
T = 2π √ (0.72 / (2 × 9.8× 0.6)
T = 2π √ ( 0.72 / 11.76)
T = 2π √0.06122
T = 2π × 0.2474
T = 1.5547 seconds
T ≈ 1.55 seconds to 2d•p
Then, the period of oscillation is 1.55seconds
Answer:
I think -7 N. Netforce is 3N-10N= -7N
Explanation:
Answer:
Explanation: Two pith ball will repel each other . they will remain balaced due to tension in the spring whose one component balances the weight and the other balances the repulsive force on each.
The gravitational force will be balanced by T cos 27.33 and the electrostatic repulsive force will be balanced by T sin27.33
So
Fg =T cos 27.33
= .55 X .888
= .49 N
Fq = T sin27.33
=.55 x .459
= .25 N.
Answer:
61440 peaks
Explanation:
A hertz represents one cycle for every second:
So if a wave have frequency of 2Hz for example, this means the wave does two cycles per second.
Normally the waves are represented by cosine or sine waves. These kind of waves have two peaks in each cycle, one positive and one negative. With this in mind, let's calculate how many peaks of the wave pass each minute.
A minute has 60 seconds, hence:
And we know already that every cycle has two peaks, so:
