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Svetach [21]
3 years ago
10

A cyclist overcomes a resistive force of 30 N in order to cycle 30 m. It takes her 6 seconds to cycle this distance. Calculate t

he power of the cyclist.
Physics
1 answer:
zmey [24]3 years ago
6 0

Answer:

Power = 15[W]

Explanation:

This problem can be solved using the work definition.

Work is equal to the product of the force by the distance, for this problem we have:

F = force = 30 [N]

d = distance = 30 [m]

w = work = F * d = 30*30 = 900 [J], "units in joules"

The power is defined as the work done in an interval of time.

P = w / t

where:

t = time [s]

therefore

P = w / t

P = 900 / 6

P = 150 [W] "units in watts"

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The maximum speed limit on interstate 10 is 75 miles per hour. how many meters per second is this
Dvinal [7]

Answer:

<h2>33.53m/s</h2>

Explanation:

Given the maximum speed limit on interstate 10 as 75 miles per hour, to get the speed in meter per seconds, we need to convert the given speed to meter per seconds.

Using the conversion 1 mile = 1609.34m and 1 hour = 3600 seconds

75 miles perhour = 75miles/1 hour

75miles/1 hour (in m/s) = 75miles*1609.34m* 1 hour/1mile * 1 hour * 3600s *

= 75 *1609.34m* 1 /1 * 1 * 3600s

= 120,700.5m/3600s

= 33.53m/s

<em>Hence the maximum speed limit on interstate 10 in metre per seconds is 33.53m/s</em>

8 0
3 years ago
Find the angle for the third-order maximum for 591 nm wavelength light falling on a diffraction grating having 1460 lines per ce
Marat540 [252]

Answer:

15.32°

Explanation:

We have given the wavelength \lambda =591nm=591\times 10^{-9}m

Diffraction grating is 1460 lines per cm

So  d=\frac{10^{-2}}{1460}=6.71\times 10^{-6}m (as 1 m=100 cm )

For maximum diffraction

dsin\Theta =m\lambda here m is order of diffraction

So 6.71\times 10^{-6}sin\Theta =3\times 591\times 10^{-9}

sin\Theta =0.264

\Theta =15.32^{\circ}

6 0
3 years ago
Real springs have mass. How will the true period andfrequency
Ad libitum [116K]

Explanation:

An perfect mass less spring, attached at one end and with a free mass attached at the other end, will have a distinct frequency of oscillation depending on its constant spring and mass. On the other hand, a spring with mass along its length will not have a characteristic frequency of oscillation.

Alternatively, based on its spring constant and mass per length, it will now have a wave Speed. It would be possible to use all wavelengths and frequencies, as long as the component fλ= S, where S is the spring wave size. If that sounds like longitudinal waves, like solid sound waves.

4 0
3 years ago
Which change would cause the largest increase in a mountain climber’s gravitational potential energy?
3241004551 [841]
<span>carrying twice the weight and climbing twice as high</span>
5 0
3 years ago
Read 2 more answers
The pressure exerted by a gas is 2.0 atm while it has a volume of 350 mL. What would be the volume of this sample of gas at stan
PSYCHO15rus [73]

Answer:

volume is 700 mL

Explanation:

pressure = 2 atm

volume = 350 mL = 0.350 L

to find out

volume

solution

we will apply here equation that is

P1×V1 = P2×V2   ..............1

here P1 = 2 and V1 = 0.350 and P2 = 1 for standard atmospheric pressure

so put all value here  in equation 1 and get V2 volume

2 × 0.350 = 1 × V2

V2 = 0.700 L

V2 = 700 mL

so volume is 700 mL

8 0
3 years ago
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