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bekas [8.4K]
3 years ago
13

A small 18 kilogram canoe is floating downriver at a speed of 1 m/s. What is the canoe's kinetic energy?

Physics
1 answer:
In-s [12.5K]3 years ago
8 0

Kinetic energy = (1/2) (mass) (speed²).

A Physicist in the canoe, or on a raft floating downriver next to the canoe, will say that the canoe's kinetic energy is zero.

A Physicist on the riverbank, watching the canoe drift by at 1 m/s, will say that its kinetic energy is 9 Joules.

They're both correct.

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A mass spectrometer is being used to separate common oxygen-16 from the much rarer oxygen-18, taken from a sample of old glacial
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Answer: 0.076 m

Explanation:

Magnetic force= centripetal force;

F(B) = F(c) --------------------------(1)

Bqv= mv^2/R---------------------(2)

Where B= magnetic field,q= charge, = mass, R= radius of the circular path.

Radius of the circular path,R= mv/qB.

Mass of oxygen-16 is 2.66e−26kg, and they are singly charged = 18/16(mass ratio= 18:16)

18/16 × (2.26 × 10^ -26 kg)

= 2.99 × 10^26 kg

∆d=2r(18)-2r(16)-----------------(3)

r(18) is the radius of mass of oxygen-18,

r(16) is the radius of mass of oxygen-16.

From the question, v= 3.7×10^6 m/s, q= 1.6×10^-9 C.

From equation (2) above we have;

R= MV/qB------------------------(4)

This equation (4) is used in solving for the distance between the two.

Solving;∆d=2r(18)-2r(16)

∆d = 2[m(18) - m(16)] v/ qB

M(18)-m(16) =(2.99-2.66)× 10^-26:

qB= 1.6×10^-19×2 = 3.2×10^-19

= (2.99-2.66)× 10^-26/ 3.2× 10^-19

= 0.076 m

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If the voltage across two oppositely charged parallel plates is kept constant, what happens to the relationship between the elec
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Answer:

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Explanation:

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