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Tema [17]
2 years ago
11

Select the correct car trips. Listed are the distances traveled by four cars and the time it took each car to cover that distanc

e. Identify which cars traveled at the same speed.

Mathematics
1 answer:
seropon [69]2 years ago
4 0

Answer:

Speeds of car 1 and car 4 are same.

Step-by-step explanation:

Speed of an object = \frac{\text{Distance traveled}}{\text{Time}}

For car 1,

Speed of car 1 = \frac{350}{5}

                        = 70 miles per hour

For car 2,

Speed of car 2 = \frac{240}{4}

                         = 60 miles per hour

For car 3,

Speed of car 3 = \frac{320}{5}

                        = 64 miles per hour

For car 4,

Speed of car 4 = \frac{420}{6}

                         = 70 miles per hour

Therefore, speeds of car 1 and car 4 are same.

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R = {10, 15, 20}
Umnica [9.8K]

Answer:

R n S = {20}

Step-by-step explanation:

n in sets means same elements found in the sets which are being compared

5 0
3 years ago
√144² = <br>√9 + √16 = <br>√9 + √16 × √400 = ​
Morgarella [4.7K]

Answer:

Step-by-step explanation

√144²

12²

144

√9 + √16

3 + 4

7

√9 + √16 × √400 = ​

3 + 2^{4} x 5

3 + 80

83

7 0
3 years ago
(3/5 - 1/2) divided by 1/2 + 1.6 x (0.3 + 0.42)
MAVERICK [17]
1.202
3/5 and 1/2 can be 6/10 and 5/10. then 0.1/2 is 0.05. for the other part, just plug 0.72 x 1.6 into a calculator.

8 0
3 years ago
You measure the lifetime of a random sample of 25 rats that are exposed to 10 Sv of radiation (the equivalent of 1000 REM), for
Slav-nsk [51]

Answer:

CI 95%(μ)= [13.506 ; 14.094]

Step-by-step explanation:

The confidence interval (CI) formula is:

CI (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proportion of the distribution tails that are outside the confidence interval. In this case, 5% because 100-90%

Z(5%/2)= is the critical value of the standardized normal distribution. In this case is 1.96

σ= standard deviation. In this case 0.75 day

mean= 13.8 days

n= number of observations . In this case 25

Then, the confidence interval (90%) is:

CI 95%(μ)= 13.8+- [1.96*(0.75/sqrt(25)]

CI 95%(μ)= 13.8+- [1.96*(0.75/5) ]

CI 95%(μ)= 13.8+- (0.294)

CI 95%(μ)= [13.8-0.294 ; 13.8+0.294]

CI 95%(μ)= [13.506 ; 14.094]

4 0
3 years ago
What is the area of an isosceles trapezoid, if its shorter base has length of 18 cm, the length of the altitude is 9 cm, and the
padilas [110]

The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).

Here, b = 18 cm and h = 9 cm.  Thus, the desired area is:

        (18 cm)(9 cm)

A = ----------------------- = 81 cm^2

                  2

This problem gives you more info than is needed to solve it.  The area of the given triangle is 81 cm^2.

5 0
3 years ago
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