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galben [10]
2 years ago
12

What is the distance between (-3,1) and (-2,-1) in units​

Mathematics
1 answer:
Nastasia [14]2 years ago
6 0

Answer:

Here is the graph I made, starting from (-3,1) to (-2,-1) it goes down 2 units and over 1 unit.

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Need help with the question that says how long is the string in centimeters.SHOW YOUR WORK!!!
Nikolay [14]
Important information:
The string is 8.5 inches long.
1 inch = 2.54 centimeters

How to solve:
Multiply both sides by 8.5 to get 8.5 inches = x centimeters.
2.54 • 8.5 = 21.59

Answer:
8.5 inches equals 21.59 centimeters.

Hope this helps! :)
4 0
3 years ago
Ava is in charge of bringing bottled water to a party that has 42 guests.
olya-2409 [2.1K]

Answer:

a - about 3 packs cause you have to round up

b - $50.76

Step-by-step explanation:

First you divide 42 and 18.

42/18=2.33

You have to round up cause you can't have half of a pack, you can't just buy half of a pack.

So, it is rounded to 3 packs.

Next you have to multiply the number of packs and the cost of each pack of water bottles.

16.92*3=$50.76

a - you have to buy 3 packs

b - the total cost is $50.76

8 0
3 years ago
Write using exponents. Work from left to right on the grid. 7*7*7*7
amm1812
7^4  the ^ is the exponent symbol if you did not know 
7^4=2,401
8 0
3 years ago
Read 2 more answers
Item 5
Nonamiya [84]

Answer:6,000

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle
Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

\int_C9y^3dx-9x^3dy

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2

\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2

\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy

⇒ -27\int\int_D(x^2 + y^2)dx dy

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta

⇒ -27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta

⇒ -27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta

⇒ -27\int\limits^{2\pi}_0 (16/4) d\theta

⇒ -108\int\limits^{2\pi}_0 d\theta

⇒ -108[2\pi - 0]

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

#SPJ4

3 0
2 years ago
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