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3 years ago

When an exponent is a negative number, we can think of it as taking the...?

Mathematics

1 answer:

STALIN [3.7K]3 years ago

5 0

Answer:

We can think of it as the zeros after the decimal point.

Step-by-step explanation:

Negative exponents always move the number to the right putting the decimal in front of it.

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A bakery sold 246 vanilla cupcakes in a day, which was 82% of the total number of cupcakes sold that day. How many total cupcake

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The total number of cupcakes were 300.

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3 years ago

PLS HELP WILL MARK BRAINLIEST!

elena-s [515]

More than means addition.

C is the correct option.

= (2x + 4) + 9 - 4y + 3x

= 2x + 4 + 9 - 4y + 3x

= 5x + 13 - 4y

= 5x - 4y + 13

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2 years ago

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3: Find the equation of the line parallel to 2x - 3y = 9, passing through the point (-6, 3)

kirza4 [7]

Your answer is C.Y=-3/2x-6

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3 years ago

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jeka57 [31]

Answer:

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Step-by-step explanation:

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3 years ago

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What is the equation of the line that passes through the points (4/5,1/5) and (1/2,3/2)?

Setler [38]

Answer:

$y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})$ point-slope form

$13x+3y=11$ (standard form)

Let me know if you prefer another form.

Step-by-step explanation:

The slope of a line can be found using $\frac{y_2-y_1}{x_2-x_1}$ provided you are given two points on the line.

We are.

Now you can use that formula. But I really love to just line up the points vertically then subtract them vertically then put 2nd difference over 1st difference.

(4/5 , 1/5)

-( 1/2 , 3/2)

-----------------

3/10 -13/10

2nd/1st = $\frac{\frac{-13}{10}}{\frac{3}{10}}=\frac{-13}{3}$ is our slope.

So the following is point-slope form for a linear equaiton:

$y-y_1=m(x-x_1) \text{ where } m \text{ is slope and } (x_1,y_1) \text{ is a point on the line }$

Plug in a point $(x_1,y_1)=(\frac{1}{2},\frac{3}{2}) \text{ and } m=\frac{-13}{3}$ .

This gives:

$y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})$

I'm going to distribute:

$y-\frac{3}{2}=\frac{-13}{3}x-\frac{-13}{6}$

Now I don't like these fractions so I'm going to multiply both sides by the least common multiply of 2,3, and 6 which is 6:

$6y-9=-26x+13$

Add 26x on both sides:

$26x+6y-9=13$

Add 9 on both sides:

$26x+6y=22$ This is actually standard form of a line.

It can be simplified though.

Divide both sides by 2:

$13x+3y=11$ (standard form)

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3 years ago

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