A = P(1 + r)^t is the interest formula
A = 1000(1 + .02)^t
A = 1000(1.02)^t
I'm not sure which of your two answers A or C have the t raised to a power but you need to choose the one with the t raised to a power.
Step-by-step explanation:
p/2 = 3/4 + p/3
p/2 - p/3 = 3/4
(3p - 2p )/6 = 3/4
p/6 = 3/4
multiply both sides by 6
p = 3×6/4
=18/4
=9/2
=4.5
Answer:
The answer to your question is letter C
Step-by-step explanation:
From the graph, we get the center and the radius
- The center is the point shown in the graph and its coordinates are (2, -1).
- The length of the radius is 4 units, from the center we count horizontally the number of squares (4)
Substitution
(x - 2)² + (y + 1)² = 4²
or (x - 2)² + (y + 1)² = 16
Volume is just length x width x height. 5 x 6 x 7 is 210. 210cm
Answer:
a) 40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.
b) 34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
a)Less than 19.5 hours?
This is the pvalue of Z when X = 19.5. So
has a pvalue of 0.4013.
40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.
b)Between 20 hours and 22 hours?
This is the pvalue of Z when X = 22 subtracted by the pvalue of Z when X = 20. So
X = 22
has a pvalue of 0.8413
X = 20
has a pvalue of 0.5
0.8413 - 0.5 = 0.3413
34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.