Answer:
The correct justifications Kelsey used to solve this equation is:
1. distributive property
2. combine like terms
3. addition property of equality
4. division property of equality
Step-by-step explanation:
Given that,
Kelsey solved the following equation:
<em>Step 1:</em>
By distributive property,
a(b + c) = ab + bc
Therefore,
<em>Step 2:</em>
Combine the like terms
7x - 4x - 1 = 6
3x - 1 = 6
Step 3:
Addition property of equality
The property means that when we add the same number to both sides of an equation, the sides remain equal
3x - 1 = 6
Add 1 on both sides
3x - 1 + 1 = 6 + 1
3x = 7
<em>Step 4:</em>
Division property of equality
The Division Property of Equality means that when we divide both sides of an equation by the same non zero number, the sides remain equal
3x = 7
Divide both sides by 3
Thus the correct justifications Kelsey used to solve this equation is:
1. distributive property. 2. combine like terms. 3. addition property of equality. 4. division property of equality
Please vote for Brainliest and I hope this helps!
Answer:
90
Step-by-step explanation:
Partition the figure by extending the sides of the ``middle'' square as shown at the right. Each original square contains four $3 \times 3$ small squares. The shaded figure consists of ten $3 \times 3$ squares, so its area is $10 \times 9 = \boxed{90\text{ square
units}}$.
Let's start with day 1:
We know that Joe practiced from 6:30 to 7:05
An hour is 60 minutes
Joe practiced for the 30 minutes left in that hour and 5 minutes into the next
30+5=35
So, he was playing for 35 minutes on the first day
Now, we can do the same thing for the second day:
He started at 3:55 and ended at 4:15
An hour is 60 minutes
<span>Joe practiced for the 5 minutes left in the hour and the first 15 minutes of the next hour
</span>
5+15=20
Now we want to add the number of minutes he practiced for both days
35+20=55 minutes
Answer:
Step-by-step explanation:
Finding an areas of a region is simple. You can take parts of that region and add them. Or you can make a guesstimate of the area of the region like solving the area of a square.