By solving a linear equation, we will see that the total cost for renting the bus is $90.
<h3>What was the total cost of renting the bus, in dollars?</h3>
Let's say that the total cost is C.
When there are 20 students, each student should pay:
p = C/20
When the other 10 students are added (for a total of 30) each student pays:
p' = C/30.
We know that the cost for each of the original 20 students decreased by $1.50, so:
p' = p - $1.50
Then we have 3 equations to work with:
p = C/20
p' = C/30.
p' = p - $1.50
Now we can replace the first and second equations into the third one:
C/30 = C/20 - $1.50
Now we can solve this linear equation for C:
C/20 - C/30 = $1.50
C*( 1/20 - 1/30) = $1.50
C*(30/600 - 20/600) = $1.50
C*(10/600) = $1.50
C*(1/60) = $1.50
C = 60*$1.50 = $90
So the total cost for renting the bus is $90.
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
Using it's concept, it is found that the domain for the expressions is, respectively, given by:
<h3>What is the domain of a function?</h3>
It is the <u>set that contains all possible input values</u>.
In a fraction, the denominator cannot be zero, hence:
- The domain of the first two expressions is of
.
- The domain of the last expression is of
.
The third expression can be simplified, as:
(x + 5)/(x + 5) = 1.
The same is true for the fourth, as:
x²/x = 1.
Neither has any restriction, hence their domain is all real numbers, represented by 
.
More can be learned about the domain of a function at brainly.com/question/25897115
Answer:
E, the heart
Step-by-step explanation:
I guess you are asking to find the sum of the first 8 terms. If so, then:
Sum = a₁(1-rⁿ)/(1-r), where a₁ is the 1st term, r=common ratio and n=number of terms:
the 1st term a₁ =3
common ratio r = - 2 (since -6/3 = - 2, and 12/-6 = - 2, etc.)
Sum = 3[(1- (-2)⁸]/(1-2) = 3(1- 256)/(1/2)
Sum = -1530
well to get decimal notation you would just multiply that out. so if you took 1.01x10^4 and multiply it out, it would equal 10,100.
