Answer:
<em>Would be the answer D(1, −4) </em>
Step-by-step explanation:
<em>Excuse me if i'm wrong, it seems like you have the same test or almost. And this was the answer on mine. I hope it works out for you!</em>
Each of the 5 saw 15 birds a day, so they saw 75 each day for 14 days. 75 times 14 is 1,050. They saw in total, 1,050 birds.
Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
Answer:
Step-by-step explanation:
