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Pachacha [2.7K]
4 years ago
5

Identify the missing nuclide in the following nuclear equation:

Chemistry
1 answer:
ra1l [238]4 years ago
7 0

Answer:

B. Bi-214.

Explanation:

The equation shows beta particle emission of 214/82 Pb which result into 214/83 Bi, in which the mass remain same but the the atomic number increases by one.

During this emission neutron get split into an electron and a proton which are represented as 0/e/-1.

So, the final nuclear equation becomes : 214/82 Pb => 0 e -1 + 214/83 Bi

Hence, the correct answer is "B. Bi-214."

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This one's just a simple math problem. Do 88 - 32, which is 56. You can also find the same answer by looking for the atomic mass of iron (Fe), which rounds up to 56.


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<h2>Question 4:</h2><h3>This equation is <em><u>balanced.</u></em></h3>

On the left side, there are 2 Chromium (Cr) and 6 Chlorine (Cl). On the right side, there are 2 Chromium and 6 Chlorine. There are 2 Chromium and 6 Chlorine on each side, therefore the equation in balanced.

~~~~~~~~~~~~~~~~~~~~~~~

If something is confusing or doesn't make any sense, feel free to let me know! ^^

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Explanation:

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