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Pachacha [2.7K]
4 years ago
5

Identify the missing nuclide in the following nuclear equation:

Chemistry
1 answer:
ra1l [238]4 years ago
7 0

Answer:

B. Bi-214.

Explanation:

The equation shows beta particle emission of 214/82 Pb which result into 214/83 Bi, in which the mass remain same but the the atomic number increases by one.

During this emission neutron get split into an electron and a proton which are represented as 0/e/-1.

So, the final nuclear equation becomes : 214/82 Pb => 0 e -1 + 214/83 Bi

Hence, the correct answer is "B. Bi-214."

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4 years ago
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What is the freezing point in °C) of a 0.743 m
lesantik [10]

Answer:

-0.276 Degrees C

Explanation:

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3 years ago
If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.45 J/g・°C) that can be heated from 22.5°C to
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Answer:

The correct answer will be "18.25 g".

Explanation:

The given values are:

Specific heat,

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q =  801 J

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ΔT = 120.0°C-22.5°C

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As we know,

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On substituting the given values, we get

⇒  0.45=\frac{801}{m(97.5)}

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3 0
4 years ago
Three grams of the same substance in different phases are stored in three different containers. Each container is barely large e
Marat540 [252]

Answer:

c.The atoms in the solid would be vibrating in position.

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Gas molecules can move vigorously here and there due very weak inter-molecular interactions and high thermal energy.

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3 years ago
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Explanation:

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3 years ago
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