4 years ago

Identify the missing nuclide in the following nuclear equation:

Chemistry

1 answer:

ra1l [238]4 years ago

7 0

Answer:

B. Bi-214.

Explanation:

The equation shows beta particle emission of 214/82 Pb which result into 214/83 Bi, in which the mass remain same but the the atomic number increases by one.

During this emission neutron get split into an electron and a proton which are represented as 0/e/-1.

So, the final nuclear equation becomes : 214/82 Pb => 0 e -1 + 214/83 Bi

Hence, the correct answer is "B. Bi-214."

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