1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pavlova-9 [17]
3 years ago
14

Please help!! I don’t think I did this right.?

Chemistry
2 answers:
harkovskaia [24]3 years ago
8 0

Answer:

It was done correctly, Your answer is completely correct.

Explanation:

iren [92.7K]3 years ago
6 0

Answer: I think you did it the right way-I think

Explanation:

Hope that helps!

Name: King

You might be interested in
What amount of energy is required to completely ionize 27.8 grams of carbon atoms in the gas phase (c(g)) if the ionization ener
zlopas [31]
I think it would be 2,510 kJ, or 2,510,000 J.
3 0
3 years ago
Which wind blows cool air inland during the day?
Korolek [52]

Answer:

Land Breeze is the answer

4 0
3 years ago
Read 2 more answers
suffixes Refer to the word parts table that you made for the words in Section 2 containing the suffix -ic. Use each of the words
Sladkaya [172]

Explanation:

need an image

3 0
3 years ago
PLEASE HELP!!!!! NEED THE ANSWER FAST!!!
PIT_PIT [208]
The answer is a. <span>changes in nucleotides of a DNA molecule that affect the genetic message.</span>
6 0
3 years ago
The rate of effusion of an unknown gas was measured and found to be 11.9 mL/min. Under identical conditions, the rate of effusio
iren2701 [21]

Answer : The correct option is, (B) CO_2

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of unknown gas = 11.9\text{ mL }min^{-1}

R_2 = rate of effusion of oxygen gas = 14.0\text{ mL }min^{-1}

M_1 = molar mass of unknown gas  = ?

M_2 = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{11.9\text{ mL }min^{-1}}{14.0\text{ mL }min^{-1}})=\sqrt{\frac{32g/mole}{M_1}}

M_1=44.2g/mole

The unknown gas could be carbon dioxide (CO_2) that has approximately 44 g/mole of molar mass.

Thus, the unknown gas could be carbon dioxide (CO_2)

5 0
3 years ago
Other questions:
  • Compare table salt and glucose
    10·1 answer
  • Calculate the concentration of H3O+ in a solution that contains 5.5 × 10-5 M OH- at 25°C. Identify the solution as acidic, basic
    5·1 answer
  • After conducting SDS-PAGE, you will conduct a staining/destaining procedure, which allows for visual identification of the prote
    12·1 answer
  • Lana balanced an equation so that the result was 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr. Which most likely represents the starting e
    12·1 answer
  • Which of the following is NOT true about equilibrium?
    14·1 answer
  • What is the surface composition of planets in the solar system?
    11·1 answer
  • Which layer of the soil profile would be affected the most by weathering and erosion?
    10·1 answer
  • At stp,250cm3 of gas had a mass of 0.36g.what result does this give for the molar mass of the gas​
    12·1 answer
  • Please Help Will Mark Brainliest!!!
    15·2 answers
  • Why does water evaperate
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!