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finlep [7]
3 years ago
13

If the cart is moving with a velocity of magnitude 29.11m/s at the top of the loop-de-loop, what must be the magnitude of the no

rmal force from track on the cart at the top?
Physics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

The Normal Force is zero.

Explanation:

The reason for the normal for to be zero is because no matter if the is a form of contact at the top, the is no force applied by the cart to loop-de-loop, and so vice versa.

If the cart was on the bottom, then the normal force would be equal to the weight of the cart, which would be te force the cart would be applying to the loo-de-loop, and therefore by newton's third law, the loop-de-loop would apply an equal force to the cart, which we would say is the normal force.

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Please someone do this <br>please ​
monitta

The various contributions involved till the chapati is made is given below.

<h3>What is food?</h3>

The substance that we intake for the body to charge up by giving nutrients is called the food.

Wheat is a staple food. We make chapati from flour obtained from the wheat grains.

The various contributions involved till the chapati is made is given below.

                 Take required amount of atta in a container

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                    Add water accordingly to form a dough

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                 Apply oil to make dough smooth for long time

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        Take small dough, make it a ball shaped and apply dry flour

                                                    ↓

               Roll it using rolling pin on the chapati maker plate

                                                    ↓

      After making it circular or any shape you want, place it on hot tawa

                                                    ↓

                               Bake it on both the sides

                                                   ↓

                                      Chapati is ready

Thus, the flow chart is made.

Learn more about food.

brainly.com/question/16327379

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6 0
2 years ago
How does the energy possessed by a ball bearing change as it travels along an incline ramp?
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4 years ago
What is the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b?
xeze [42]

The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

<h3>Change in energy level of the electron</h3>

When photons jump from a higher energy level to a lower level, they emit or radiate energy.

The change in energy level of the electrons is calculated as follows;

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