All categories

4 years ago

Explain why it is not advisable to use small values of i in performing triangular glass prism experiment

Physics

1 answer:

kifflom [539]4 years ago

7 0

Is this about using triangular prisms in spectrometer experiments ? See enclosed

You might be interested in

What is the impulse of a 1700 kg truck traveling at 22.5 m/s?

andrew-mc [135]

Impulse is just the product of mass and speed!

I = 1700 * 22.5 = 38,250 kg m/s

It does not have any special name for its units :(

3 0

3 years ago

The Doppler effect causes sounds moving toward an observer to sound _____.

vladimir1956 [14]

Answer: softer

The sound waves become weaker, so to an observer this wave is lighter sound.

8 0

3 years ago

Read 2 more answers

Which option describes the direction of thermal energy transfer in Earth's

Montano1993 [528]

.........

Explanation:

Option B..... ...

4 0

3 years ago

Read 2 more answers

Image caught on Screen is called

bixtya [17]

Answer:

<h2>Virtual image</h2>

Explanation:

<h3>Virtual image can be caught on a screen</h3>

hope this helps you.

will give the brainliest!

follow ~Hi1315~

4 0

3 years ago

Read 2 more answers

Water flows through a cast steel pipe (k = 50 W m.K, ε = 0.8) with an outer diameter of 104mm and 2 mm wall thickness. Calculate

masha68 [24]

Answer:

The heat loss per unit length is $\frac{Q}{L} = 2981 W/m$

Explanation:

From the question we are told that

The outer diameter of the pipe is $d = 104mm = \frac{104}{1000} = 0.104 m$

The thickness is $D = 2mm = \frac{2}{1000} = 0.002m$

The temperature of water is $T = 90^oC = 90 + 273 = 363K$

The outside air temperature is $T_a = -10^oC = -10 +273 = 263K$

The water side heat transfer coefficient is $z_1 = 300 W/ m^2 \cdot K$

The heat transfer coefficient is $z_2 = 20 W/m^2 \cdot K$

The heat lost per unit length is mathematically represented as

$\frac{Q}{L} = \frac{2 \pi (T - Ta)}{ \frac{ln [\frac{d}{D} ]}{z_1} + \frac{ln [\frac{d}{D} ]}{z_2}}$

Substituting values

$\frac{Q}{L} = \frac{2 * 3.142 (363 - 263)}{ \frac{ln [\frac{0.104}{0.002} ]}{300} + \frac{ln [\frac{0.104}{0.002} ]}{20}}$

$\frac{Q}{L} = \frac{628}{0.2107}$

$\frac{Q}{L} = 2981 W/m$

6 0

3 years ago