Answer:
his movement is proportional to the intensity of the earthquake,
Explanation:
An earthquake is a record of the intensity of an earthquake as a function of time.
Where the intensity is plotted on the y-axis, which corresponds to the vertical movement of the detector, this movement is proportional to the intensity of the earthquake, therefore the intensity increases the amplitude of the oscillation increases.
And the in x corresponds to time
Answer:
distance between object and image = 18.9 cm
Explanation:
given data
radius of curvature = 18 cm
focal length = 1/2 radius of curvature
magnification = 40%
to find out
distance between object and image
solution
we know lens formula that is
1/f = 1/v + 1/u ....................1
here f = 18 /2 and v and u is object and image distance
and we know m = 40% = 0.40
so 0.40 = -v / u
so here v = - 0.40 u
so from equation 1
1/f = 1/v + 1/u
2/18 = - 1/0.40u + 1/u
u = -13.5 cm ..................2
and
v = -0.40 (- 13.5)
v = 5.4 cm ......................3
so from equation 2 and 3
distance between object and image = 5.4 + 13.5
distance between object and image = 18.9 cm
the key result indicate that how you will achieve the your goal
Answer:
100 cm
Explanation:
It is given that there are two loudspeakers that produces along x-axis.
The maximum intensity of the sound is at a distance of = 15 cm apart.
The sound intensity becomes zero when the separation between the speakers are increased and becomes 65 cm.
Therefore, the sound waves are in the phase,
The sound waves are out of phase when
Therefore,
= 2 (65 - 15)
= 2 x 50
= 100 cm
Hence the wavelength of the sound is 100 cm.