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3 years ago

Examples of uniform speed

Physics

2 answers:

Stella [2.4K]3 years ago

6 0

Answer:

A body is said to be moving with uniform speed, if it covers equal distances in equal intervals of time. ...

MAVERICK [17]3 years ago

5 0

Answer:

yeet is the answer to the question lol

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Two identical satellites are in orbit about the earth. One orbit has a radius r and the other 2r. The centripetal force on the s

velikii [3]

Answer:

the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

Explanation:

Mass of satellite, m

orbit radius of first, r1 = r

orbit radius of second, r2 = 2r

Centripetal force is given by

$F= \frac{mv^{2}}{r}$

Where v be the orbital velocity, which is given by

$v=\sqrt{gr}$

So, the centripetal force is given by

$F= \frac{mgr}}{r}}=mg$

where, g bet the acceleration due to gravity

$g=\frac{GM}{r^{2}}$

So, the centripetal force

$F= \frac{GMm}}{r^{2}}}$

Gravitational force on the satellite having larger orbit

$F= \frac{GMm}{4r^{2}}$ .... (1)

Gravitational force on the satellite having smaller orbit

$F'= \frac{GMm}{r^{2}}$ .... (2)

Comparing (1) and (2),

F' = 4 F

So, the centripetal force on the satellite in the larger orbit is _one fourth_ as that on the satellite in the smaller orbit.

8 0

3 years ago

A car of mass 998 kilograms moving in the positive y–axis at a speed of

aksik [14]

The total momentum should come out to be <span>2.0 x 10^4 kilogram meters/second </span>

8 0

3 years ago

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Please help <br>Newton second law of motion is F =ma <br>

mamaluj [8]

Answer: ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

Explanation: Newton's second law of motion is F = ma, or force is equal to mass times acceleration.

6 0

2 years ago

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What kind of object are the light rays interacting with in the model below?

Ymorist [56]

Answer:

Concave lens

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5 0

2 years ago

An 80-kg man is skating northward and happens to suddenly collide with a 20-kg boy who is ice skating toward the east. Immediate

Fantom [35]

Answer:

6.25 m/s

Explanation:

mass of man (m1) = 80 kg

mass of boy (m2) = 20 kg

mass of man and boy after collision (m12)= 20 + 80 = 100 kg

velocity of man and boy after collision (v) = 2.5 m/s

angle θ = 60 °

How fast was the boy moving just before the collision ?

From the diagram attached, the first image shows the man and the boys motion while the second diagram shows their motion rearranged to form a triangle. With the momentum of the man and the boy forming the sides of the triangle.
M₁₂ = total momentum after collision = m12 x v = 100 x 2.5 = 250
Mboy = momentum of the boy before collision = m2 x Velocity of boy
Mman = momentum of the man before collision = m1 x velocity of man
from the triangle, cos θ = $\frac{Mboy}{M₁₂}$

cos 60 = $\frac{Mboy}{250}$

Mboy = 250 x cos 60 = 125

recall that momentum of the boy (Mboy) also = m2 x Velocity of boy

therefore

125 = 20 x velocity of boy

velocity of boy = 125 / 20 = 6.25 m/s

4 0

3 years ago

Examples of uniform speed​

Examples of uniform speed