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Nastasia [14]
3 years ago
8

How does Bohr’s model of the atom compare with Thomson’s model?

Physics
2 answers:
Mars2501 [29]3 years ago
6 0
<span>They both describe atoms as being made up of positive and negative matter</span>
larisa [96]3 years ago
4 0

Answer:

They both describe atoms as being made up of positive and negative matter.

Explanation:

In both Bohr's model and Thomson model, the atom consists of positively-charged matter and negatively-charged matter. However, the structure of the atom in the two models is totally different:

- in Thomson's model, the atom consists of a large sphere of uniform positive charge, and electrons (which are negatively charged) are scattered all around inside this sphere

- In Bohr's model, the atom consists of a small, positively charged nucleus, while the electrons (negatively charged) orbit around the nucleus in precise orbits.

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When the rock or soil of Earth’s surface is moved to another location by water, ice, or wind
levacccp [35]
The answer is deposition/A. Please mark brainliest.
8 0
3 years ago
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It's a snowy day and you're pulling a friend along a
NeX [460]

The coefficient of friction between the sled and the snow is 0.119.

To find the answer, we need to know about the friction.

<h3>How to find the coefficient of friction between the sled and the snow?</h3>
  • Whenever a body moves over the surface of another body, a force come into play, which acts parallel to the surface of contact and oppose the relative motion. This opposing force is called friction.
  • To solve the problem, we have to draw the free body diagram of the given system.
  • We have given with the following values,

                                     a=0\\\alpha =35^0\\T=75N\\m=57kg

Here, acceleration will be equal to zero, because the velocity is given as constant.

  • Thus, from the diagram, we can write the balancing equations as follows,

                                      ma=Tcos\alpha -f\\\where\\f=kN\\\N+Tsin\alpha=mg\\Thus,\\N=mg-Tsin\alpha

  • Substituting N in f and f in the equation of ma, then we get,

                   ma= Tcos\alpha -k(mg-Tsin\alpha )

  • Substituting values, we get the coefficient of friction as,

                    0=(75*cos35)-k((57*9.8)-(75sin35))\\\\k((57*9.8)-(75sin35))=(75*cos35)\\\\515.6k=61.44\\\\k=\frac{61.44}{515.6}=0.119

Thus, we can conclude that, the coefficient of friction between the sled and the snow is 0.119.

Learn more about the friction here:

brainly.com/question/28107059

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6 0
1 year ago
Read 2 more answers
How much time will have passed by the time a sample of an isotope has decayed to 6.25% of its original mass if the half-life is
aleksandrvk [35]

Answer:

60 days.

Explanation:

Let the original mass (N₀) = 1 g

Amount remaining (N) = 6.25% of its original mass

= 6.25% × 1

= 6.25/100 × 1

= 0.0625 g

Half life (t½) = 15 days

Time (t) =?

Next, we shall determine the rate of decay. This can be obtained as follow:

Decay constant (K) = 0.693/ half life

K = 0.693 / t½

Half life (t½) = 15 days

Decay constant (K) =?

K = 0.693 / t½

K = 0.693 / 15

K = 0.0462 / day

Finally, we shall determine the time taken for the sample of the isotope to decay to 6.25% of its original mass.

This can be obtained as follow:

Original amount (N₀) = 1 g

Amount remaining (N) = 0.0625 g

Decay constant (K) = 0.0462 / day

Time (t) =?

Log (N₀/N) = Kt/2.3

Log (1/0.0625) = 0.0462 × t / 2.3

Log 16 = 0.0462 × t / 2.3

1.2041 = 0.0462 × t /2.3

Cross multiply

0.0462 × t = 1.2041 × 2.3

Divide both side by 0.0462

t = (1.2041 × 2.3)/0.0462

t = 59.9 ≈ 60 days

Therefore, the time taken for the sample of the isotope to decay to 6.25% of its original mass is 60 days

5 0
3 years ago
The main difference between speed and velocity involves
mezya [45]
The main difference between speed and velocity is A: direction.
4 0
3 years ago
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An iron anchor of density 7850.00 kg/m3 appears 183 N lighter in water than in air.
andrew11 [14]
<h2>a) Volume of anchor is 0.019 m³</h2><h2>b) Weight of anchor in air is 1463.17 N</h2>

Explanation:

a) Weight loss in water = Volume of object x density of water x acceleration due to gravity

183 = Volume of anchor x 1000 x 9.81

Volume of anchor = 0.019 m³

b) Weight = Mass x acceleration due to gravity = Volume x Density x acceleration due to gravity

Weight of anchor in air = Volume of anchor x Density of anchor x acceleration due to gravity

Weight of anchor in air = 0.019 x 7850 x 9.81 = 1463.17 N

Weight of anchor in air = 1463.17 N

3 0
3 years ago
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