<span>What we need to first do is split the ball's velocity into vertical and horizontal components. To do that multiply by the sin or cos depending upon if you're looking for the horizontal or vertical component. If you're uncertain as to which is which, look at the angle in relationship to 45 degrees. If the angle is less than 45 degrees, the larger value will be the horizontal speed, if the angle is greater than 45 degrees, the larger value will be the vertical speed. So let's calculate the velocities
sin(35)*18 m/s = 0.573576436 * 18 m/s = 10.32437585 m/s
cos(35)*18 m/s = 0.819152044 * 18 m/s = 14.7447368 m/s
Since our angle is less than 45 degrees, the higher velocity is our horizontal velocity which is 14.7447368 m/s.
To get the x positions for each moment in time, simply multiply the time by the horizontal speed. So
0.50 s * 14.7447368 m/s = 7.372368399 m
1.00 s * 14.7447368 m/s = 14.7447368 m
1.50 s * 14.7447368 m/s = 22.1171052 m
2.00 s * 14.7447368 m/s = 29.48947359 m
Rounding the results to 1 decimal place gives
0.50 s = 7.4 m
1.00 s = 14.7 m
1.50 s = 22.1 m
2.00 s = 29.5 m</span>
Answer:
L = 8694 Kg.m²/s
Explanation:
r = 270 ĵ m
v = 14 î m/s
m = 2.3 kg
θ = 90º
L = ?
We can apply the equation
L = m*v*r*Sin θ
L = (2.3 kg)*(14 m/s)*(270 m)*Sin 90º = 8694 Kg.m²/s
Answer:
It represents the change in charge Q from time t = a to t = b
Explanation:
As given in the question the current is defined as the derivative of charge.
I(t) = dQ(t)/dt ..... (i)
But if we take the inegral of the equation (i) for the time interval from t=a to
t =b we get
Q =∫_a^b▒〖I(t) 〗 dt
which shows the change in charge Q from time t = a to t = b. Form here we can say that, change in charge is defiend as the integral of current for specific interval of time.
<em><u>Answer </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>In</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>light</u></em><em><u> </u></em><em><u>wave</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>prop</u></em><em><u>erty</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>wave</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>tells</u></em><em><u> </u></em><em><u>about</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>col</u></em><em><u>or</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>light</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>it</u></em><em><u>'s</u></em><em><u> </u></em><em><u>Wavel</u></em><em><u>ength</u></em><em><u> </u></em><em><u>.</u></em><em><u> </u></em><em><u> </u></em>
<em><u>Wavel</u></em><em><u>ength</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>distan</u></em><em><u>ce</u></em><em><u> between</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>crest</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>through</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u>also</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>dist</u></em><em><u>ance</u></em><em><u> </u></em><em><u>after</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>wave</u></em><em><u> </u></em><em><u>repe</u></em><em><u>at</u></em><em><u> </u></em><em><u>its</u></em><em><u>elf</u></em><em><u> </u></em><em><u>!</u></em>
<em><u>It's</u></em><em><u> </u></em><em><u>SI</u></em><em><u> </u></em><em><u>unit</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>meter</u></em><em><u> </u></em><em><u>!</u></em><em><u> </u></em>
<em><u>It</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>scalar</u></em><em><u> </u></em><em><u>quan</u></em><em><u>tity</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>
<em><u>Diff</u></em><em><u>erent</u></em><em><u> </u></em><em><u>Wavelength</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>light</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>diff</u></em><em><u>erent</u></em><em><u> </u></em><em><u>col</u></em><em><u>or</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>
<h2>• VIBGYOR </h2>
i.e, Violent , Indigo , Blue , Green , Yellow Orange, and Red along with their shades are the colors which we can see !!
• They almost range from 400nm to 700nm ( visible range of light )
True because friction happens when two things are rubbed against each other and it creates force and sliding something vigorously against something else can create force.