Answer:
'Daniela had a 5-meter head start, and Leonard caught up to her at 25 meters.'
Explanation:
hope that helps :)
Answer: D. The elements have the same number of valence electrons
Explanation: The chemical reactivity of elements is governed by the valence electrons present in the element.
The elements present in the same group or vertical column have similar valence configurations and thus behave similarly in chemical reactions or have similar bonding properties.
For Example: Both fluorine and chlorine belong to same family or group and both have 7 electrons in their valence shell and thus accept single electron to attain noble gas configuration.




thus both would bond with a cation bearing a single positive charge.
Answer:
Explanation:
Given
speed of Electron 
final speed of Electron 
distance traveled 
using equation of motion

where v=Final velocity
u=initial velocity
a=acceleration
s=displacement


acceleration is given by 
where q=charge of electron
m=mass of electron
E=electric Field strength

Answer:
1 question is- I believe 4. Melting Question 2 is Density
Explanation:
THOUGHT ABOUT IT!!!
Answer:
C 0.85 j/g*k
Explanation:
The specific heat capacity of a material is given by:

where
Q is the amount of heat supplied to the object
m is the mass of the object
is the increase in temperature of the object
For the object in this problem, we have
m = 117 g is the mass
Q = 1200 J is the heat supplied
is the increase in temperature
Substituting into the formula, we find the specific heat:
