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user100 [1]
3 years ago
11

Infrared observations of the orbits of stars close to the galactic center indicate a small object at the center with a mass of a

bout how many solar masses?
Physics
1 answer:
MariettaO [177]3 years ago
5 0

Answer:

(4.31±0.38) million Solar masses.

Explanation:

The galactic center is the center of the milky way around which the galaxy rotates. It is most likely the location of a supermassive black hole which has a mass of (4.31±0.38) million Solar masses. The location is called Sagittarius A*.

As there is interstellar dust in our line of sight from the Earth infrared observations need to be taken.

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Which best describes the history of scientific knowledge?
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A path of inferences guided to be cherry picked as for which ones were reasonable and which ones had no ability in the real world to sustain in scientific law
8 0
4 years ago
hich one of the following statements could be an operational definition of electric current?View Available Hint(s)Which one of t
klemol [59]

Answer:

it is True as the operational definition of electric current.

Explanation:

The definition of electric current is

         I = dQ / dt

By convention the direction of the current is the direction in which a positive charge flows.

The initial expression is the derivative that is the change of the load in the unit of time and this occurs in a given cross-sectional cable.

The proposed definition is the same as this, so it is True as the operational definition of electric current.

8 0
3 years ago
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
4 years ago
A control clinic offers a program that guarantees a weight loss of up to 0.46 kg in one week. Express the weight loss in a ratio
Mice21 [21]

Answer:

0.76 mg/s

Explanation:

0.46 kg/week × (1 week / 7 days) × (1 day / 24 hrs) × (1 hr / 3600 s) × (1000 g/kg) × (1000 mg/g) = 0.76 mg/s

4 0
3 years ago
A book is moved once around the perimeter of a tabletop with dimensions 1.2 m x 1.8 m.
Goryan [66]

Answer:

a) 0m

b) 6m

Explanation:

First, we need to remember:

Displacement: Difference between final and initial position.

Distance traveled: Total distance traveled.

a) If the final position is the same as the initial position, then:

final position = initial position

And we know that:

displacement = final position - initial position = 0

Then the displacement of the book is zero.

b)

We can assume that the book traveled along the perimeter of the table.

The table is a rectangle of width 1.2m and length 1.8m

Remember that for a rectangle of width W and length L, the perimeter is:

P = 2*L + 2*W

Then the perimeter of the table is:

P = 2*1.2m + 2*1.8m = 6m

This means that the distance traveled by the book is 6 meters.

3 0
2 years ago
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