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user100 [1]
3 years ago
11

Infrared observations of the orbits of stars close to the galactic center indicate a small object at the center with a mass of a

bout how many solar masses?
Physics
1 answer:
MariettaO [177]3 years ago
5 0

Answer:

(4.31±0.38) million Solar masses.

Explanation:

The galactic center is the center of the milky way around which the galaxy rotates. It is most likely the location of a supermassive black hole which has a mass of (4.31±0.38) million Solar masses. The location is called Sagittarius A*.

As there is interstellar dust in our line of sight from the Earth infrared observations need to be taken.

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How would I use “Newton#1: Laws of Motion” in a sentence?
Anit [1.1K]

You would say "in Newtons !st law (state what it is) then continue on with the rest of your sentence! ;3

3 0
3 years ago
Please help, thank you !
kherson [118]

Answer:

0.04658 m from the nut

Explanation:

Recall that torque is defined as the vector product of force (F) times distance (d). Then, given that the force is applied perpendicular to the wrench, gives the sine of the angle (90 degrees) equal to 1, simplifying the calculation which consists basically on solving for d in the equation:

2.25 N*m = 48.3 N * d

d = 2.25 /48.3  m ≈ 0.04658 m

6 0
3 years ago
A huge block of stone has a mass of 650kg and gains 70000j of gpe. how high has it been raised? (g = 10m/s2 )
Anna35 [415]
The formula for calculating GPE is

GPE = m x h x g

Where m is mass, h is height raised and g is gravity.

To solve the problem we just have to substitute the values we are given

70,000J = 650 x 10 x y

70,000J = 6500 x y

70,000 / 6500 = y

10.769 = y

So, the block of stone has been raised approximately 10.769 metres.
5 0
2 years ago
Charged particles q1=− 4.80 nC and q2=+ 4.80 nC are separated by distance 3.00 mm , forming an electric dipole. The charges are
Dafna1 [17]

Answer:

Electric field, E = 936.19 N/C

Explanation:

It is given that,

Charge 1, q_1=-4.8\ nC=-4.8\times 10^{-9}\ C

Charge 2, q_2=+4.8\ nC=+4.8\times 10^{-9}\ C

Distance between them, d = 3 mm = 0.003 m

Torque, \tau=8\times 10^{-9}\ N-m

Angle between electric field and line connecting the charge, \theta=36.4^{\circ}

We need to find the torque exerted on the dipole. The torque experienced by the dipole in the electric field is given by :

\tau=pE\ sin\theta

p is the dipole moment, p=qd

\tau=qdE\ sin\theta

E=\dfrac{\tau}{qd\ sin\theta}

E=\dfrac{8\times 10^{-9}}{4.8\times 10^{-9}\times 0.003\ sin(36.4)}

E = 936.19 N/C

So, the magnitude of electric field on the dipole is 936.19 N/C. Hence, this is the required solution.

5 0
3 years ago
How much energy is transported across a
irina1246 [14]

Explanation:

Let us assume that Z is the energy transported across an area of 1.00 cm^{2} per hour by an electromagnetic wave with an r.m.s speed of 21.5 V/m.

Therefore, first we will calculate the current as follows.

                  I = \frac{E_{rms^{2}}}{c \times \mu_{o}}

                    = \frac{10^{-4} \times 3600 \times (21.5)^{2}}{3 \times 10^{8} \times 4 \times 3.14 \times 10^{-7}}

                    = 0.441 J

Therefore, we can conclude that 0.441 J energy is transported across a given EM wave.

4 0
3 years ago
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