Answer:
25 psi
Explanation:
The weight of the car is:
W = mg
W = 1550 kg * 9.8 m/s²
W = 15,190 N
Divided by 4 tires, each tire supports:
F = W/4
F = 15,190 N / 4
F = 3797.5 N
Pressure is force divided by area, so:
P = F / A
P = (3797.5 N) / (0.16 m × 0.14 m)
P ≈ 170,000 Pa
101,325 Pa is the same as 14.7 psi, so:
P ≈ 170,000 Pa × (14.7 psi / 101,325 Pa)
P ≈ 25 psi
Air is the example of mixture
The answer I'm pretty sure is 3
<span>79.75m/s .................................</span>
The frequency of oscillation is 2.153 Hz
What is the frequency of spring?
Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.
For the mass-spring system in this problem,
The Frequency of spring is calculated with the equation:

Where,
f = frequency of spring
k = spring constant = 64 N/m
m = mass attached to spring = 350g = 0.350 kg
a = maximum acceleration = 5.3 m/s^2
Substituting the values in the equation,



Hence,
The frequency of oscillation is 2.153 Hz
Learn more about frequency here:
<u>brainly.com/question/13978015</u>
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