All categories

2 years ago

Gravitational potential is the energy due to an object's:

Physics

2 answers:

Radda [10]2 years ago

7 0

Answer:

The answer is C. position in a gravity field

butalik [34]2 years ago

4 0

position in a gravitation field (c)

You might be interested in

A 75.0 Ohm resistor uses 0.285 W of power. What is the voltage across the resistor?

Brilliant_brown [7]

Answer:4.62

Explanation:

Acellus

6 0

2 years ago

A typical mattress has a network of springs that provide support. If you sit on a mattress, the springs compress. A heavier pers

GenaCL600 [577]

Answer:

Explanation:

Spring has a tendency to store energy in them and deform its shape when force is applied on it. Once the applied force is removed it regains its original shape and size.

It is in helical shape and is used in mattress to give structure and support. Spring have elastic nature and follows spring forces, F = k * x

where is the applied force, k is the spring constant and x is the amount of extension.

When a heavier person sits on a mattress, more weight is applied on springs and they form coils, as weight is removed they regains its shape again.

4 0

2 years ago

Someone please help me

Lapatulllka [165]

False... I hope that helps ;)

6 0

2 years ago

A ping pong ball with a dent in it can be put into a pan of boiling water. After a short amount of time, the dent will pop out.

kifflom [539]

heat from water goes into air in ball

air expands

ping goes the dent

6 0

2 years ago

Read 2 more answers

A magnetic field is uniform over a flat, horizontal circular region with a radius of 1.50 mm, and the field varies with time. In

atroni [7]

Answer:

The average induced emf around the border of the circular region is $8.48\times 10^{-5}\ V$ .

Explanation:

Given that,

Radius of circular region, r = 1.5 mm

Initial magnetic field, B = 0

Final magnetic field, B' = 1.5 T

The magnetic field is pointing upward when viewed from above, perpendicular to the circular plane in a time of 125 ms. We need to find the average induced emf around the border of the circular region. It is given by the rate of change of magnetic flux as :

$\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=A\dfrac{-d(B'-B)}{dt}\\\\\epsilon=\pi (1.5\times 10^{-3})^2\times \dfrac{1.5}{0.125}\\\\\epsilon=8.48\times 10^{-5}\ V$

So, the average induced emf around the border of the circular region is $8.48\times 10^{-5}\ V$ .

6 0

2 years ago

Read 2 more answers