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gregori [183]
3 years ago
10

B is the midpoint of AC. If AB= X +5 and BC = 2X -11, find the measure of AB

Mathematics
2 answers:
Murljashka [212]3 years ago
5 0
First, you know that B is the mid point, meaning AB is equal to BC. Therefore, you can set up the equation: x+5=2x-11. Then, you solve for x. Once you are done solving, you should get 16. Hope this helps!
Dahasolnce [82]3 years ago
3 0
Hi! Actually, the answer is 21. Because x+5 and 2x-11 are equivalent, set them equal to one another in an equation. Solve for x

You can see my steps in the picture i attached for you!!

Then, once you have x, you need to plug it back in to the expression x+5 (AB) to get 21. I hope this helps you!! :))

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Answer:

x=2,\:y=-16

Step-by-step explanation:

\begin{bmatrix}-8x+y=-32\\ -3x-10=y\end{bmatrix}\\\\\mathrm{Isolate}\:x\:\mathrm{for}\:-8x+y=-32:\quad x=-\frac{-32-y}{8}\\\\\mathrm{Subsititute\:}x=-\frac{-32-y}{8}\\\begin{bmatrix}-3\left(-\frac{-32-y}{8}\right)-10=y\end{bmatrix}\\\\Simplify\\\begin{bmatrix}\frac{3\left(-32-y\right)}{8}-10=y\end{bmatrix}\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:\frac{3\left(-32-y\right)}{8}-10=y:\quad y=-16\\\\\mathrm{For\:}x=-\frac{-32-y}{8}\\\\\mathrm{Subsititute\:}y=-16\\x=-\frac{-32-\left(-16\right)}{8}\\

-\frac{-32-\left(-16\right)}{8}=2\\x=2\\x=2,\:y=-16

3 0
3 years ago
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Answer:

The answer is (d) ⇒ pq^{2}r\sqrt[3]{pr^{2}}

Step-by-step explanation:

* To simplify the cube roots:

 If its number then the number must be written in the form x³

 then we divide the power by 3 to cancel the radical

 If its variable we divide its power by 3 to cancel the radical

∵ \sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}

∴ p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}

∵ p^{\frac{1}{3}}=\sqrt[3]{p}

∵ r^{\frac{2}{3}}=\sqrt[3]{r^{2}}

∴ p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})

∴ prq^{2}\sqrt[3]{pr^{2}}}

∴ The answer is (d)

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