Answer:
See a tractor is more slow but has a greater force and a car is fast but has a slower force
Explanation:
so your answer is Tractors have more force then cars
Answer:
f' = 3665.51 Hz
Explanation:
given,
speed of the hawk = 24.7 m/s
frequency of screech emitted by the hawk = 3400 Hz
speed of sound = 331 m/s
By Doppler's effect

f' is the frequency received by the mouse
v is the speed of the sound
v_s is the speed of the hawk
now,

f' = 1.078 x 3400
f' = 3665.51 Hz
The frequency received by the stationary mouse is equal to 3665.51 Hz
if it is heat flow through a metal, it would be necessary to have a conductor so that the electrons can flow through it (delocalised electrons).
In terms of radiation, it would require a good absorber of heat (e.g. a black surface) so that the thermal energy flows through on the surface area.
A philosopher (i think) because he's asking a question about society.
Answer:
x=L/2 y=0 and the charge q3 is ¼ of the charge q
Explanation:
For this exercise we will use Coulomb's law.
F₁₂ = k q₁ q₂ / r₁₂²
From this expression we see that like charges repel and charges of different signs attract.
Let's apply this expression to our case, they indicate that the two charges are of equal magnitude and sign, therefore the force is repulsive, so that it is in equilibrium with a third charge (q₃) this must be of the opposite sign and be between the two charge (q)
let's apply Newton's second law to one of the charges, for example the one on the left
-F₁₂ + F₁₃ = 0
F₁₂ = F₁₃
k q₁ q₂ / r₁₂² = k q₁ q₃ / r₁₃²
q₂ / r₁₂² = q₃ / r₁₃²
q₃ = q₂ (r₁₃ / r₁₂)²
The problem indicates the charge q₁ = q₂ = 4 q and the distance between them is r₁₂ = L = 9 cm = 0.09 m, we substitute
q₃ = 4q (r₁₃ / L)²
Let's analyze the situation a bit that the charge 1 and 2 are in equilibrium with a single charge 3 this must be symmetrical between the two charge (the same force), therefore its position on the x axis must be r₁₃ = L/2 and how it is on the y axis = 0
let's substitute
q₃ = 4q (L / 2L)²
q₃ = 4q 1/4
q₃ = q
the charge q3 is ¼ of the charge q