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3 years ago

What are the answers?

Physics

1 answer:

White raven [17]3 years ago

3 0

19 incisions me know the status of my order if it is still mad at me for not get to the you're not get the email from the other side of all of zoee the present time the way back to the house to get to the bank to get to go home and get it done today if that works with each of cuts off the present moment and pay the rest of the day off to work till 12 pm on my way to work till 12 the way home and then she was so happy to see me now that the weather is for a call from a present from my home computer and lighter than the one the best teacher and she is doing better but it's 6 this is only for school tomorrow and lighter note to self don't know how much much more to say but it's the best thing that ever since the way home from my way to the airport now waiting now to get to go home yesterday the present and lighter and will not have the money to give the present and lighter than the last time she said she was confused on what time to pick me know what the next steps are the best teacher ever since that was so sweet and pay pay being in my home computer now but i no this is the first I've heard of it before and pay for it but it's 6 your phone so if it's ok I'll answer the present and the way they were he was going to call from my phone to the bank to see me today and pay the present moment and lighter than the last time to pick up the present moment to look for school and pay the way to the end of zoee the woods and lighter and pay the rest of the day so i no your fine if not then I'll have no internet at school today to see how it said that she said she was so happy dance class now and then and there at school tomorrow so that she could see the woods with our new home and then and pay for school tomorrow on my way back to the bank to the airport now to see me now or hey hey hey i was just typing random words

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How much time will it take for a truck to travel 20 meters if it is traveling at 4 m/s?

ss7ja [257]

Answer:

<h2>The answer is 5 s</h2>

Explanation:

The time taken can be found by using the formula

$t = \frac{d}{v} \\$

d is the distance

v is the velocity

From the question we have

$t = \frac{20}{4} \\$

We have the final answer as

Hope this helps you

4 0

3 years ago

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polet [3.4K]

Answer:

kinetic and potential

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3 years ago

How many type of linear expansion physic

Katena32 [7]

three types

The three types of thermal expansions are Linear expansion , Superficial expansion and Cubical expansion.

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3 years ago

A group of science and engineering students embarks on a quest to make an electrostatic projectile launcher. For their first tri

vekshin1

Electric charge on the plastic cube: $1.3\cdot 10^{-7}C$

Explanation:

The electric potential around a charged sphere (such as the Van der Graaf) generator is given by

$V(r)=\frac{kQ}{r}$

where

k is the Coulomb's constant

Q is the charge on the sphere

r is the distance from the centre of the sphere

Here we have:

V = 200,000 V on the surface of the sphere, so at r = 12.0 cm

We need to find the voltage V' at 2.0 cm from the edge of the sphere, so at

r' = 12.0 + 2.0 = 14.0 cm

Since the voltage is inversely proportional to r, we can use:

$Vr=V'r'\\V'=\frac{Vr}{r'}=\frac{(200,000)(12.0)}{14.0}=171,429 V$

This is the potential at the location of the plastic cube.

Now we can use the law of conservation of energy, which states that the initial electric potential energy of the cube is totally converted into kinetic energy when the plastic cube is at infinite distance from the generator. So we can write:

$qV' = \frac{1}{2}mv^2$

where:

q is the charge on the plastic cube

V' is the potential at the location of the cube

m = 5.0 g = 0.005 kg is the mass of the cube

v = 3.0 m/s is the final speed of the cube

Solving for q, we find the charge on the cube:

$q=\frac{mv^2}{2V'}=\frac{(0.005)(3.0)^2}{2(171,429)}=1.3\cdot 10^{-7}C$

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

7 0

3 years ago

On august 10, 1972, a large meteorite skipped across the atmosphere above the western united states and western canada, much lik

RUDIKE [14]

(a)
The velocity of the meteorite just before hitting the ground is:
$v=20 km/s=20000 m/s$
The loss of energy of the meteorite corresponds to the kinetic energy the meteorite had just before hitting the ground, so:
$\Delta K = \frac{1}{2}mv^2= \frac{1}{2}(3.4 \cdot 10^6 kg)(20000 m/s)^2=6.8 \cdot 10^{14}J$

(b) 1 megaton of tnt is equal to $1 MT=4.2 \cdot 10^{15}J$
To find to how many megatons the meteorite energy loss $\Delta E$
corresponds, we can set the following proportion
$1 MT: 4.2 \cdot 10^{15}J=x: \Delta E$
And so we find
$x= \frac{\Delta E}{4.2 \cdot 10^{15}J} = \frac{6.8 \cdot 10^{14}J }{4.2 \cdot 10^{15}J} =0.162 MT$
So, 0.162 megatons.

(c) 1 Hiroshima bomb is equivalent to 13 kilotons (13 kT). The impact of the meteorite had an energy of $\Delta E=0.162 MT=162 kT$ . So, to find to how many hiroshima bombs it corresponds, we can set the following proportion:
$1:13 kT=x:162 kT$
And so we find
$x= \frac{162 kT}{13 kT}=12.46$
So, the energy released by the impact of the meteorite corresponds to the energy of 12.46 hiroshima bombs.

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4 years ago